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JulijaS [17]
2 years ago
8

It is 4:12 p.m. Emma's mom will be home from work in 70 minutes, and Emma has gymnastics lessons at 6:00 p.m.

Mathematics
1 answer:
egoroff_w [7]2 years ago
8 0

Answer:

emma is dum as freak

Step-by-step explanation:

.................................................

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X + 2y + 5z = -17<br> 2x – 3y + 2z = -16<br> 3x + y - z = 3
Tatiana [17]

Answer:

first one : x=−2y−5z−17

2nd one: x= 3 /2 y−z−8

3rd one: x= −1 /3 y+ 1 /3 z+1

Step-by-step explanation:

8 0
3 years ago
Aless and Louis are going to put a rectangular pool in their backyard. The cost of installation is $6,000. If the dimensions of
lana [24]

Answer:

cost of the pool per cubic meters = $5

Step-by-step explanation:

The rectangular pool has a dimension of 30 m by 20 m by 2 m. To know the cost of the pool per cubic meter we have to calculate the volume of the pool . Then divide the total cost of the pool by it volume.

volume of the rectangular pool = length × height × width

volume of the rectangular pool = 30 × 20 × 2

volume of the rectangular pool = 1200  m²

The cost of installation is $6000 . The volume of the pool is 1200 cubic meters.

cost per cubic meters = total cost of installation/volume

cost per cubic meters = 6000/1200

cost of the pool per cubic meters = $5

7 0
3 years ago
Hi yes I have more questions theyre in the pics as well as here
navik [9.2K]

Answer:

1.-6

Step-by-step explanation:

I don't know how to do the second one but

BD = DC

x+8 = 3x+2

2x=-4

x=-2

-6+12

-6

5 0
3 years ago
Help pls OOOFFIES AND ASAP
Nimfa-mama [501]

Answer:

it is

Step-by-step explanation:

0.75. or that's at least what Google told me

5 0
3 years ago
Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,
sweet [91]

Answer:

Hence, the particular solution of the differential equation is y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x.

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

f'' = x - \frac{3}{2}

f' = \int {\left(x-\frac{3}{2}\right) } \, dx

f' = \int {x} \, dx -\frac{3}{2}\int \, dx

f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C, where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative (f'(4) = 1):

1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C

C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)

C = -1

The first derivative is y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1, and the particular solution is found by integrating one more time and using the initial condition (f(0) = 0):

y = \int {\left(\frac{1}{2}\cdot x^{2}-\frac{3}{2}\cdot x -1  \right)} \, dx

y = \frac{1}{2}\int {x^{2}} \, dx - \frac{3}{2}\int {x} \, dx - \int \, dx

y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x + C

C = 0 - \frac{1}{6}\cdot 0^{3} + \frac{3}{4}\cdot 0^{2} + 0

C = 0

Hence, the particular solution of the differential equation is y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x.

5 0
3 years ago
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