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luda_lava [24]
3 years ago
9

Term of the arithmetic sequence 12, 10, 8

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
7 0

Answer:

\mathtt{\huge\star{\pink{\underline{ 12,\: 10,\: 8,\: 6,\:4,\:2,\:-1,/:-3........ infinite      }}}}\huge\star

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I would like some assistance please.
butalik [34]

Answer:

2

Step-by-step explanation:

Range is the highest number of plots minus the lowest number, in this case it would be 3-1

6 0
3 years ago
Find the output, k, when the input, t, is -7−7minus, 7.<br> k = 10t-19k=10t−19
sleet_krkn [62]

The value of k is -89

Explanation:

The given expression is k=10t-19

We need to determine the output k, when the input t is -7

<u>Output k:</u>

The value of the output k can be determined by substituting the input t=-7 in the expression k=10t-19

Thus, we have,

k=10(-7)-19

Multiplying the terms 10 and -7, we have,

k=-70-19

Simplifying, we get,

k=-89

Thus, the value of k is -89

7 0
3 years ago
How to solve this problem -5-3x-x-(-16)
Tcecarenko [31]

Answer:

11 - 4x

Step-by-step explanation:

-5 - 3x - x - (-16)

Reorder the terms so that like terms are next to each other

-5 - (-16) - 3x - x

Combine like terms

11 - 4x

4 0
3 years ago
Read 2 more answers
Will give you 300 Brainley points please help
Dennis_Churaev [7]

Answer

Theair no error because theair the answer ni the steps And all its ok

Step-by-step explanation:

6 0
3 years ago
During the 7th examination of the Offspring cohort in the Framingham Heart Study, there were 1219 participants being treated for
AlexFokin [52]

Answer:

95% confidence interval for the proportion of the population which are on treatment is [0.3293 , 0.3607].

Step-by-step explanation:

We are given that during the 7th examination of the Offspring cohort in the Framing ham Heart Study, there were 1219 participants being treated for hypertension and 2,313 who were not on treatment.

The sample proportion is :  \hat p = x/n = 1219/3532 = 0.345

Firstly, the pivotal quantity for 95% confidence interval for the proportion of the population is given by;

      P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion = 0.345

           n = sample of participants = 3532

           p = population proportion

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the population​ proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level of

                                                         significance are -1.96 & 1.96}

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u>= [\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }]

    = [ 0.345-1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } } , 0.345+1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } } ]

    = [0.3293 , 0.3607]

Hence, 95% confidence interval for the proportion of the population which are on treatment is [0.3293 , 0.3607].

6 0
3 years ago
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