We are given with the function summation of 16*(5) ^(I-1) from 1 to infinity. As we assume in the calculator that infinity is equal to a very large number, the result that can be obtained is undefined. This means the number is very large. This is because the ratio (15) is large too. The series is divergent since the number in the infinite geometric series is ever increasing. Answer is B.
I think it’s D, sorry if I’m wrong.
We take the equation <span>d = -16t^2+12t</span> and subtract d from both sides to get
0<span> = -16t^2+12t - d
We apply the quadratic formula to solve for t. With a = -16, b = 12, c = -d, we have
t = [ -(12) </span><span>± √( 12^2 - 4(-16)(-d) ) ] / [2 * -16]</span>
= [- 12 ± √(144-64d) ] / (-32)
= [- 12 ± √16(9-4d)] / (-32)
= [- 12 ± 4√(9-4d)] / (-32)
= 3/8 ±√(9-4d) / 8
The answer to your question is t = 3/8 ±√(9-4d) / 8
Answer:
Should be $300
let me know if it's correct:)
