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Pani-rosa [81]
3 years ago
11

Moles are rodents very similar to mice. They typically live underground, spending most of their lives below the earth's surface.

Mice, on the other hand, may dig burrows to nest and sleep in, but they spend much of their time above ground. Their nests can be made of cloth, hair, and hay. Because moles live underground, they have developed differently than mice.
What adaptation would you expect to see in moles?


A) Moles have developed special claws used for clutching their young.

B) Moles have developed markings that help them identify one another.

C) Moles have developed a special pouch to keep newborn mole babies in.

D) Moles have developed a membrane that can keep dirt out of their eyes.
Mathematics
1 answer:
HACTEHA [7]3 years ago
5 0

Answer:

D)

Step-by-step explanation:

We will analyze each answer to find the correct one.

A) Moles have developed special claws used for clutching their young.

Although they may have developed they make more sense than they have developed is to dig in the ground, it has nothing to do with grabbing the young.

B) Moles have developed markings that help them identify one another.

There is no context with the statement of the question

C) Moles have developed a special pouch to keep newborn mole babies in.

It would make sense since your children are born in burrows below the ground, but even without this special bag the moles can survive.

D) Moles have developed a membrane that can keep dirt out of their eyes.

This is the correct answer as it is the one that makes the most sense, because when digging, the ideal is that they develop a type of protection because of this.

The answer is D.

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siniylev [52]

Answer:

option (a) It will be closer to 30 than to 20

Step-by-step explanation:

Data provided in the question:

For sample 1:

n₁ = 10

variance, s₁² = 20

For sample 2:

n₂ = 15

variance, s₂² = 30

Now,

The pooled variance is calculated using the formula,

S^{2}_{p} = \frac{(n_{1}-1)\times s^{2}_{1} +(n_{2}-1)\times s^{2}_{2}}{n_{1}+n_{2}-2}

on substituting the given respective values, we get

S^{2}_{p} = \frac{(10-1)\times 20 +(15-1)\times 30}{10+15-2}

or

S^{2}_{p} = 26.0869

Hence,

the pooled variance will be closer to 30 than to 20

Therefore,

The correct answer is option (a) It will be closer to 30 than to 20

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Step-by-step explanation:

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Step-by-step explanation:

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