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Sonja [21]
3 years ago
14

Write the slope-intercept form of an equation for the line passing through -2, 8 and (-4, -4)

Mathematics
2 answers:
KonstantinChe [14]3 years ago
6 0
Find slope: (-4-8)/(-4+2) = -12/-2 = 6
Y = 6x + b
Plug in a point
8 = 6(-2) + b, b = 20
Equation: y = 6x + 20
algol [13]3 years ago
6 0
It’s what they said.
Ok
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NEED HELP ASAP!!!!! WILL GIVE BRAINLIEST!!!!!!!
Mama L [17]
Maybe b or c I guess??
3 0
2 years ago
Read 2 more answers
A trapezoid has an area of 13.5 square inches. If the bases are 3 and 6 inches what is the height?
liraira [26]
Well the formula is : b1+b2/2 (h)

so the height would be solved as : 
13.5 = 3+6/2 (h)
13.5 = 9/2 (h)
h = (13.5)/(9/2)
h = (13.5) x (2/9)  *reciprocal*
h = (27) / (9)
h = 3


5 0
3 years ago
Algebra
vladimir2022 [97]
(2x + 3y = 12) x (-2)
(4x - 3y = 6) x 1

-4x - 6y = -24
4x - 3y = 6

You can cancel out the x values by adding the two equations together. 
(-4x + 4x) + (-6y - 3y) = (-24 + 6)
-9y = -18
y = 2

Solve for x now...
4x - 3(2) = 6
4x - 6 = 6
4x = 12
x = 3

Check... (x = 3, y = 2)
2(3) + 3(2) = 12 
6 + 6 = 12
12 = 12 <- this works! 

4(3) - 3(2) = 6
12 - 6 = 6
6 = 6 <- this works!
5 0
3 years ago
Read 2 more answers
-6 - 3(2x + 4) = 18what’s the answer
Brrunno [24]

Answer:

x=-6

Step-by-step explanation:

-6-3\left(2x+4\right)=18

Add 6 to both sides:

-6-3\left(2x+4\right)+6=18+6

-3\left(2x+4\right)=24

Divide both sides by -3:

\frac{-3\left(2x+4\right)}{-3}=\frac{24}{-3}

2x+4=-8

Subtract 4 from both sides:

2x+4-4=-8-4

2x=-12

Divide both sides by 2:

\frac{2x}{2}=\frac{-12}{2}

x=-6

7 0
3 years ago
A graph displays point A (5, 3, 4) and point B (−4, 2, 6). Calculate the approximate distance each point is from the origin. Rou
SIZIF [17.4K]

Distance from the origin to the points  ≈ 0.41.

<h3>What is the distance between two points ( p,q) and (x,y)?</h3>

The shortest distance (length of the straight line segment's length connecting both given points) between points ( p,q) and (x,y) is:

D = √[(x-p)² + (y-q)²]  

Point A (5, 3, 4) and point B (−4, 2, 6) are located away from the origin (0,0,0), and the points from the origin to this points are expressed as OB - OA where;

Let OB is the distance from the origin to the point B

Let OA is the distance from the origin to the point A

Using the formula for calculating the distance between two points;

OA = √(z2-z1)²+(y2-y1)²+(x2-x1)²

OA = √(4-0)²+(3-0)²+(5-0)²

OA = √(16)+(9)+(25)

OA = √50

OA = 7.071

Similarly;

OB = √(6-0)²+(2-0)²+(-4-0)²

OB = √(6)²+(2)²+(-4)²

OB = √36+4+16

OB = √56

OB = 7.4833

Distance from the origin to the points = 7.4833 - 7.071= 0.4123

Distance from the origin to the points  ≈ 0.41

Learn more about distance between two points here:

brainly.com/question/16410393

#SPJ1

5 0
1 year ago
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