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Sonja [21]
3 years ago
14

Write the slope-intercept form of an equation for the line passing through -2, 8 and (-4, -4)

Mathematics
2 answers:
KonstantinChe [14]3 years ago
6 0
Find slope: (-4-8)/(-4+2) = -12/-2 = 6
Y = 6x + b
Plug in a point
8 = 6(-2) + b, b = 20
Equation: y = 6x + 20
algol [13]3 years ago
6 0
It’s what they said.
Ok
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Valentin [98]
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7 0
3 years ago
Which represents the solution(s) of the system of equations, y = x2 – 4x – 21 and y = –5x – 22? Determine the solution set algeb
hodyreva [135]
Hello,

With
y=x²-4x-21
y=-5x-22

==>x²-4x-21=-5x-22
==>x²+x+1=0

In R, no solution for Δ=1-4=-3<0


3 0
3 years ago
Read 2 more answers
The average weight of 7 potted plants is 23 pounds. An 8th potted plant is added to the pallet,
cluponka [151]

Answer:

The weight of the 8th plant is 39lb

Step-by-step explanation:

Given:

Average Weight of 7 plants = 23lb

Average Weight of 8 plants = 25lb

Required:

Weight of the 8th plant

To solve this, the total weight of the initial 7 plants need to be calculated;

Average = \frac{Sum-of-weights}{Number-of-Plants}

Substitute 23 for Average and 7 for Number of plants

23 = \frac{Sum-of-weights}{7}

Multiply both sides by 7

7 * 23 = \frac{Sum-of-weights}{7} * 7

161 = Sum-of-weights

Hence, the 7 plants weigh 161

Represent the weight of the 8th plant with E

When the 8th plant is added;

The sum of the weight becomes 161 + E

And the number of plants becomes 8

The average is calculated as thus

Average = \frac{Sum-of-weights}{Number-of-Plants}

25 = \frac{161 + E}{8}

Multiply both sides by 8

8 * 25 = \frac{161 + E}{8} * 8

200 = 161 + E

Subtract 161 from both sides

200  -161 = 161 - 161 + E

39 = E

Reorder

E = 39

Hence, the weight of the 8th plant is 39lb

6 0
3 years ago
PLZZZ HURRYYY ILL GIVE YOU BRAINIEST<br><br><br> What are the x-intercepts?
Alinara [238K]

Answer:

The x-intercepts are 0, 1, 2, 2.2

Step-by-step explanation:

Hope this helps if it answers your question

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6 0
3 years ago
A complex number z_1z 1 ​ z, start subscript, 1, end subscript has a magnitude |z_1|=13∣z 1 ​ ∣=13vertical bar, z, start subscri
docker41 [41]

Answer:

z_1 = \sqrt{84.5} - i \, sin(\sqrt{84.5})

Step-by-step explanation:

z_1 has the following properties:

|z_1| = 13

\theta = 315 º = 1.75 π (π = 180º)

therefore, z₁ = 13 * [ cos(1.75 π) + i sin(1.75 π) ] =  13*[cos(1.75π - 2π) + i sin(1.75π - 2π)] = 13*[cos(-π/4) + i sin(-π/4)] {this is due to periodicity} = 13*(√2/2 - i  √2/2) = \sqrt{84.5} - i \, sin(\sqrt{84.5})

6 0
4 years ago
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