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Sonja [21]
3 years ago
14

Write the slope-intercept form of an equation for the line passing through -2, 8 and (-4, -4)

Mathematics
2 answers:
KonstantinChe [14]3 years ago
6 0
Find slope: (-4-8)/(-4+2) = -12/-2 = 6
Y = 6x + b
Plug in a point
8 = 6(-2) + b, b = 20
Equation: y = 6x + 20
algol [13]3 years ago
6 0
It’s what they said.
Ok
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Please help me!!!!!!!! :)​
nirvana33 [79]

Answer:

Step-by-step explanation:

the 30 year olds are more likely to pick chocolate as their favorite ice cream because the fraction of people who like chocolate is 14/20 where the other 3 are 4/20 and 2/20. this can be converted into percentages as well by multipling by 5. 70% of people who are in their 30s like chocolate opposed to the 20% and 10%.

3 0
3 years ago
In this exercise, we show that the orthogonal distance d from the plane p with equation
kodGreya [7K]
Use the cross product to find the orthogonal vector, solve the parametric equation to see at which (t) the point + orthogonal vector intersects the plane, the distance is (t) * norm of vector
3 0
3 years ago
Factor 4k^2-49 and m^3+3m^2-4m-12
NNADVOKAT [17]
<span> m = 3 m = 2 m = -2 </span><span>Factor 4k^2-49 and m^3+3m^2-4m-12</span>
7 0
3 years ago
What is the slope of the line that passes through (3,-7) and (-1,1)
mafiozo [28]

the slope would be the change in Y over the change in X,

-7-1= -8, 3-(-1)= 4, -8/4 or -2 is the slope

3 0
3 years ago
Read 2 more answers
Please help with any of this Im stuck and having trouble with pre calc is it basic triogmetric identities using quotient and rec
german

How I was taught all of these problems is in terms of r, x, and y. Where sin = y/r, cos = x/r, tan = y/x, csc = r/y, sec = r/x, cot = x/y. That is how I will designate all of the specific pieces in each problem.

#3

Let's start with sin here. \frac{2\sqrt{5}}{5} = \frac{2}{\sqrt{5}} Therefore, because sin is y/r, r = \sqrt{5} and y = +2. Moving over to cot, which is x/y, x = -1, and y = 2. We know y has to be positive because it is positive in our given value of sin. Now, to find cos, we have to do x/r.

cos = \frac{-1}{\sqrt{5}} = \frac{-\sqrt{5}}{5}

#4

Let's start with secant here. Secant is r/x, where r (the length value/hypotenuse) cannot be negative. So, r = 9 and x = -7. Moving over to tan, x must still equal -7, and y = 4\sqrt{2}. Now, to find csc, we have to do r/y.

csc = \frac{9}{4\sqrt{2}} = \frac{9\sqrt{2}}{8}

The pythagorean identities are

sin^2 + cos^2 = 1,

1 + cot^2 = csc^2,

tan^2 + 1 = sec^2.

#5

Let's take a look at the information given here. We know that cos = -3/4, and sin (the y value), must be greater than 0. To find sin, we can use the first pythagorean identity.

sin^2 + (-3/4)^2 = 1

sin^2 + 9/16 = 1

sin^2 = 7/16

sin = \sqrt{7/16} = \frac{\sqrt{7}}{4}

Now to find tan using a pythagorean identity, we'll first need to find sec. sec is the inverse/reciprocal of cos, so therefore sec = -4/3. Now, we can use the third trigonometric identity to find tan, just as we did for sin. And, since we know that our y value is positive, and our x value is negative, tan will be negative.

tan^2 + 1 = (-4/3)^2

tan^2 + 1 = 16/9

tan^2 = 7/9

tan = -\sqrt{7/9} = \frac{-\sqrt{7}}{3}

#6

Let's take a look at the information given here. If we know that csc is negative, then our y value must also be negative (r will never be negative). So, if cot must be positive, then our x value must also be negative (a negative divided by a negative makes a positive). Let's use the second pythagorean identity to solve for cot.

1 + cot^2 = (\frac{-\sqrt{6}}{2})^{2}

1 + cot^2 = 6/4

cot^2 = 2/4

cot = \frac{\sqrt{2}}{2}

tan = \sqrt{2}

Next, we can use the third trigonometric identity to solve for sec. Remember that we can get tan from cot, and cos from sec. And, from what we determined in the beginning, sec/cos will be negative.

(\frac{2}{\sqrt{2}})^2 + 1 = sec^2

4/2 + 1 = sec^2

2 + 1 = sec^2

sec^2 = 3

sec = -\sqrt{3}

cos = \frac{-\sqrt{3}}{3}

Hope this helps!! :)

3 0
2 years ago
Read 2 more answers
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