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3 years ago

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X+5y=15 I need to solve for x and y

1 answer:

vampirchik [111]3 years ago

4 0

Hi there!

Solve for x
$x + 5y = 15$

Subtract 5y from both sides.
$x = 15 - 5y$

----------------------

Solve for y
$x + 5y = 15$

Subtract x from both sides.
$5y = 15 - x$

Divide both sides by 5.
$y = 3 - \frac{1}{5} x$

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Answer:

(20,5) is NOT a solution of the equation $6x+10y=150$ .

The point (20,5) implies that there are 20 small tables and 5 large tables.

Step-by-step explanation:

We have been given that a catering company is expecting 150 people to attend the wedding. There are two types of tables, ones which can fit 6 people and ones which can fit 10 people.

If there are x tables which can fit 6 people and there are y tables which can fit 10 people, we can express the total number of people that can fit on all available tables as: $6x+10y$ .

Since there are total 150 people expected in the wedding, the equation can be framed as: $6x+10y=150$ .

Let us check if the point (20,5) is a solution of the equation.

$6*20+10*5=150$

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Since we get a false statement, therefore, (20,5) is NOT a solution of the equation $6x+10y=150$ .

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A basketball-player scores a free-throw with probability 0.9. What is the probability that her first miss occurs on the 6th shot

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Answer:

$Pr = 0.059049$

Step-by-step explanation:

Given

$p = 0.9$ --- probability of scoring

Required

Probability that his first miss is his 6th shot

Let q represent the event that he did not score.

Using complement rule:

$q = 1 - p = 1 - 0.9 = 0.1$

The event that his first miss is his 6th is represented as:

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So, the probability is:

$Pr = p^5 * q$

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3 years ago