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Studentka2010 [4]
3 years ago
15

The length of a rectangle is four times its width. if the area of the rectangle is 400 yd2 , find its perimeter.

Mathematics
2 answers:
Rus_ich [418]3 years ago
5 0
I don’t know for sure but the length is 40 and the width is 10.
hram777 [196]3 years ago
3 0
Let W = width, and L = length.

L = 4W

A = LW

400 = (4W)(W)

400 = 4w^2

4W^2 = 400

W^2 = 100

W = 10

The width is 10 yd, and the length is 40 yd.
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Answer:

The answer to your question is below

Step-by-step explanation:

Process

1.- Get two points of each line to find the equation of each line

   Continuous line    A (-10, 0)  B (0, 9)

   Dotted line            C (-2, -3)   D (0, -10)

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 Slope dotted line     m = \frac{-10 + 3}{0 + 2} = \frac{-7}{2}

2.- Get the equation of each line

     Continuous line    y + 0 = 9/10 (x + 10)

                                   y = 9/10x + 9

      Dotted line          y + 3 = -7/2(x + 2)

                                    y + 3 = -7/2x - 7

                                    y = -7/2x -7 - 3

                                    y = -7/2x - 10

3.- Find the inequalities

   <u> Continuous line</u> (we need the upper area of the line, we use ≥)

                               y ≥ 9/10x + 9

   The <u>Dotted line</u> (we also need the upper area, we use >)

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6 0
3 years ago
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Yanka [14]
For this case we have the following expression:
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constants A and B are:
 
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