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Veseljchak [2.6K]
3 years ago
6

What is the first term of an AP whose common difference is 2 and 31st term begin -88

Mathematics
2 answers:
castortr0y [4]3 years ago
4 0

Answer:

a₁ = - 148

Step-by-step explanation:

The n th term of an AP is

a_{n = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given d = 2 and a₃₁ = - 88 , then

a₁ + (30 × 2) = - 88

a₁ + 60 = - 88 ( subtract 60 from both sides )

a₁ = - 148

lisabon 2012 [21]3 years ago
3 0

 

a₁ = - 148

Step-by-step explanation:

The n th term of an AP is

= a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given d = 2 and a₃₁ = - 88 , then

a₁ + (30 × 2) = - 88

a₁ + 60 = - 88 ( subtract 60 from both sides )

a₁ = - 148

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