What is the first term of an AP whose common difference is 2 and 31st term begin -88
2 answers:
Answer:
a₁ = - 148
Step-by-step explanation:
The n th term of an AP is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given d = 2 and a₃₁ = - 88 , then
a₁ + (30 × 2) = - 88
a₁ + 60 = - 88 ( subtract 60 from both sides )
a₁ = - 148
a₁ = - 148
Step-by-step explanation:
The n th term of an AP is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given d = 2 and a₃₁ = - 88 , then
a₁ + (30 × 2) = - 88
a₁ + 60 = - 88 ( subtract 60 from both sides )
a₁ = - 148
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