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erastovalidia [21]

3 years ago

12

Each dimension of a rectangular family room is 3.5 times larger than the rectangular bedroom. if it costs $312 to carpet the bed

room, how much would cost to carpet the family room with the same carpet?

2 answers:

Oksana_A [137]3 years ago

7 0

Answer:

$3822

Step-by-step explanation:

We are given that Each dimension of a rectangular family room is 3.5 times larger than the rectangular bedroom.

So, length of a rectangular family room must be 3.5 times larger than rectangular bedroom.

And Breadth of a rectangular family room must be 3.5 times larger than rectangular bedroom.

So, area of rectangular family room must be larger than rectangular bedroom by $3.5^2 =12.25$ times

So, Area of rectangular family room must be 12.25 times larger than rectangular bedroom

Now cost of carpet for bedroom = $312

So, cost of same carpet for family room = $312 \times 12.25$

= $3822$

Hence the cost to carpet the family room is $3822.

Deffense [45]3 years ago

3 0

So,

I'm assuming that this is a simple multiplication problem.

All we have to do (I'm assuming) is multiply 312 by 3.5.
312 * 3.5 = $1092

It will cost $1092 to carpet the family room with the same carpet.

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$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

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Required

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$\triangle CBA {\displaystyle \sim } \triangle FED$ $\triangle CBA {\displaystyle \sim } \triangle FDE$ $\triangle BAC {\displaystyle \sim } \triangle EFD$

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The given triangles, implies that:

$A {\displaystyle \sim } \ D$

$B {\displaystyle \sim } \ E$

$C {\displaystyle \sim } \ F$

By taking each sides of both triangle, one after the other; the possible similar triangles are:

$\triangle ABC {\displaystyle \sim } \triangle DE\ F$

$\triangle CBA {\displaystyle \sim } \triangle FED$

$\triangle BAC {\displaystyle \sim } \triangle EDF$

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