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nikklg [1K]
3 years ago
14

Which numbers are perfect squares? Check all that apply.

Mathematics
2 answers:
-Dominant- [34]3 years ago
3 0
The number that is a perfect square is 16
Citrus2011 [14]3 years ago
3 0
1,16,100 are perfect squares
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Which expression is equivalent to 2(x+7)-18+4/5 ?
Vadim26 [7]

Answer:

4.7/5

Step-by-step explanation:

7 0
2 years ago
Write <img src="https://tex.z-dn.net/?f=%28-%20x%5E%7B2%7D%29%20-4x%2B2" id="TexFormula1" title="(- x^{2}) -4x+2" alt="(- x^{2})
marin [14]
Because the coefficient of x^2 is -1, we know that a will be -1.  Knowing that the coefficient of x is -4, we can calculate that p=2.  Thus, we have -1(x+2)^2+q is our equation.  This is equal to -x^2-4x-4+q.  As the constant term must be 2, we can then see that q is 6.

As such, we have -1(x+2)^2+6=0 as our factorization.

To solve this equation, we can use the quadratic formula.  Plugging in values, we have:

\frac{4+-2 \sqrt{6} }{-2}
which is equal to: (when the fraction is simplified)
-2+- \sqrt{6}
7 0
3 years ago
Can someone help me with this math homework please!
mamaluj [8]

Answer:

The rock hits the ground between <u>2</u> seconds and <u>2.5</u> seconds after it is dropped

Step-by-step explanation:

The given table is presented as follows;

\begin{array}{ccl}t&h(t)&Description\\0&20&Initial \ height\\0.5&18.8&Rock \ in \ downward \ motion\\1&15.1&\\1.5&9&\\2&0.4&The \ height \ just \ before \ the \ rock \ hits \ the \ ground \\2.5&-10.6&The \ calculated \ height \ after\ the \ rock \ hits \ the \ ground \\3&-24.1&Calculated \ height \ after\ the \ rock \ hits \ the \ ground\end{array}

Therefore, the rock hits the ground between t = 2 seconds and t = 2.5 seconds after it is dropped.

4 0
3 years ago
Which expression is equivalent to (7x3)2(x3)?
astraxan [27]

Answer:

(21)+(6) is an equivalent expression

Step-by-step explanation:

(7x3)2(x3)

(21)+(6)

8 0
3 years ago
Please help me with this question!! I also need the steps
e-lub [12.9K]

Hi there!

\large\boxed{x = \frac{\pi}{3} \text{ and } \pi}

We are given:

cos(7x)cos(4x) = -1 - sin(7x)sin(4x)

Begin by moving all terms with variables to one side:

cos(7x)cos(4x) + sin(7x)sin(4x) = -1

The corresponding trig identity is cos(A - B). Thus:

cos(7x - 4x) = cos(7x)cos(4x) + sin(7x)sin(4x) = -1

cos(3x) = -1

cos = -1 at  π, so:

3x = π

x = π/3

We can also find another solution. Let 3π = -1:

3x = 3π

x = π

Thus, solutions on [0, 2π) are π/3 and π.

8 0
3 years ago
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