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marta [7]
10 months ago
9

What are the zeros of the function f (x) = (x-6)(2x+10)

Mathematics
1 answer:
bazaltina [42]10 months ago
6 0

Let f(x)=0.

(x-6)(2x+10)=0

Using the zero-factor property, equate each factor to 0 and then solve for x.

\begin{gathered} x-6=0 \\ x=6 \\  \\ 2x+10=0 \\ 2x=-10 \\ x=-\frac{10}{2} \\ x=-5 \end{gathered}

Thus, the zeros of the given function are 6 and -5.

The zeros are the x-coordinate where the graph touches the x-axis.

Thus, the x-coordinates of where the graph touches the x-axis are -5, and 6.

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F is a polynomial of degree 6. f has a root of multiplicity
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Answer:

f(x) = 0.43 * (x - 3)^{2}  * (x-1)^{3}*(x + 10)

Step-by-step explanation:

We have a 6th degree polynomial  f(x)

r = 3 is a root of f with multiplicity 2

r = 1 is a root of f with multiplicity 3

f(-5) = -29721.6

f(-10) = 0

Then:  f(x) = a*((x -3)^2 ) * ((x - 1)^3)*(x + 10)

f(-5) = a *  (-8)^2 *  (-6)^3  *  (5)  =  -29,721.6

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a =  -29,721.6/-69,120

a =  0.43

so

f(x) = 0.43 * (x - 3)^{2}  * (x-1)^{3}*(x + 10)

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3 years ago
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Leno4ka [110]
12 and 1/8, I just simplified 2/16 to 1/8
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In circle C with m \angle BCD= 46m∠BCD=46 and BC=3BC=3 units, find the length of arc BD. Round to the nearest hundredth.
jolli1 [7]

The length of arc of the given circle, to the nearest hundreth, is: 2.41 units.

<h3>What is the Length of an Arc?</h3>

Length of arc = ∅/360 × 2πr, where the radius of the circle is r, and the reference angle is ∅.

We are given the following:

Radius (r) = 3 units

Reference angle (∅) = 46°

Plug in the values into the length of arc formula:

Length of arc = 46/360 × 2π(3)

Length of arc = 2.41 units.

Therefore, the length of arc of the given circle, to the nearest hundreth, is: 2.41 units.

Learn more about length of arc on:

brainly.com/question/2005046

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Answer:

i = -7/12

Step-by-step explanation:

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Identify the coefficient of -13x
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Answer:

-13

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