Quadratic
y = ax^2 + bx + d
c (x) = ax^2 + bx + d
c (3) = a (3^2) + b (3) + d
c (3) = 9a + 3b + d = 15.50
c (7) = a (7^2 + b (7) + d
c (7) = 49a + 7b + d = 23.50
c (12) = a (12^2) + b (12) + d
c (12) = 144a + 12b + d = 56
solve using simultaneous equations... to get a b and d
use that to solve for x = 5
hope this helps?
Answer:
It will cost 11 cents a day.
Step-by-step explanation:
1.98/18=11
plzz have brainiest
Answer: 32x^7y^15
Step-by-step explanation:
(x)^2(2xy^3)^5
= x^2 * 32x^5y^15
= 32x^7y^15
If 2X=2(x-3)
2x=2x-6
The equation has no real solutions.
