Let the point be P, and the masses be located at P1 and P2.
The centre of mass is such that the moments of masses m1 and m2 exert an equal moment at the point P,
and the distance P1P2=d
namely,
m1(mPP1)=m2(mPP2)
The distance of the centre of mass from m1 is therefore
d1=d*m2/(m1+m2)
Similarly, the distance of the centre of mass from m2 is
d2=d*m1/(m1+m2)
The derivative of
at a point
in the direction of a vector
is

We have

and

Then the derivative at
in the direction of
is

Answer:
3x2 + 2x - 63x2 + 2x - 6
Step-by-step explanation:
X= 135 and Y = 15. Hope that helps!