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lawyer [7]
3 years ago
15

Ice cream: A certain ice cream parlor offers fifteen flavors of ice cream. You want an ice cream cone with three scoops of ice c

ream, all different flavors.
Part 1 of 2
In how many ways can you choose a cone if it matters which flavor is on top, which is in the middle and which is on the bottom?
de
The number of ways to choose a cone, if order matters, is
Mathematics
1 answer:
masha68 [24]3 years ago
8 0

Answer:

The number of ways to choose a cone, if order matters, is 45.

Step-by-step explanation:

Given that a certain ice cream parlor offers fifteen flavors of ice cream, and you want an ice cream cone with three scoops of ice cream, all different flavors, to determine in how many ways you can choose a cone if it matters which flavor is on. top, which is in the middle and which is on the bottom, the following calculation must be performed:

15 x 3 = X

45 = X

The number of ways to choose a cone, if order matters, is 45.

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PLEASE HELP I WILL GIVE BRAINLIEST!!
inysia [295]

Answer:

43.96

Step-by-step explanation:

To find Circumference the formula is

2*3.14*R=C

replace R with your radious which is 7

2*3.14*7=43.96

6 0
3 years ago
Please help me fill in the missing number ​
adelina 88 [10]

Answer:

6

Step-by-step explanation:

3/4 / 6 = 3/4 x 1/6, which equals 3/24

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8 0
3 years ago
Consider the following differential equation. x^2y' + xy = 3 (a) Show that every member of the family of functions y = (3ln(x) +
Veronika [31]

Answer:

Verified

y(x) = \frac{3Ln(x) + 3}{x}

y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{x}

Step-by-step explanation:

Question:-

- We are given the following non-homogeneous ODE as follows:

                           x^2y' +xy = 3

- A general solution to the above ODE is also given as:

                          y = \frac{3Ln(x) + C  }{x}

- We are to prove that every member of the family of curves defined by the above given function ( y ) is indeed a solution to the given ODE.

Solution:-

- To determine the validity of the solution we will first compute the first derivative of the given function ( y ) as follows. Apply the quotient rule.

                          y' = \frac{\frac{d}{dx}( 3Ln(x) + C ) . x - ( 3Ln(x) + C ) . \frac{d}{dx} (x)  }{x^2} \\\\y' = \frac{\frac{3}{x}.x - ( 3Ln(x) + C ).(1)}{x^2} \\\\y' = - \frac{3Ln(x) + C - 3}{x^2}

- Now we will plug in the evaluated first derivative ( y' ) and function ( y ) into the given ODE and prove that right hand side is equal to the left hand side of the equality as follows:

                          -\frac{3Ln(x) + C - 3}{x^2}.x^2 + \frac{3Ln(x) + C}{x}.x = 3\\\\-3Ln(x) - C + 3 + 3Ln(x) + C= 3\\\\3 = 3

- The equality holds true for all values of " C "; hence, the function ( y ) is the general solution to the given ODE.

- To determine the complete solution subjected to the initial conditions y (1) = 3. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

                         y( 1 ) = \frac{3Ln(1) + C }{1} = 3\\\\0 + C = 3, C = 3

- Therefore, the complete solution to the given ODE can be expressed as:

                        y ( x ) = \frac{3Ln(x) + 3 }{x}

- To determine the complete solution subjected to the initial conditions y (3) = 1. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

                         y(3) = \frac{3Ln(3) + C}{3} = 1\\\\y(3) = 3Ln(3) + C = 3\\\\C = 3 - 3Ln(3)

- Therefore, the complete solution to the given ODE can be expressed as:

                        y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{y}

                           

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6 0
3 years ago
Solve for u. You must write your answer in fully simplified form.<br><br> -5u = -3
densk [106]
After dividing & simplifying you will get u= 5/3.
7 0
3 years ago
I will give you a little brainliest
aalyn [17]

Answer:

C

Step-by-step explanation:

C

6 0
2 years ago
Read 2 more answers
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