Answer:
The answer is below
Step-by-step explanation:
1. COST Mr. Rivera wants to purchase a riding lawn mower, which is on sale for 15% off the marked price. The store charges sales tax 6.5% on all sales. Write a function p(x) that represents the price after a 15% discount. Write a function t(x) that represents the total cost with sales tax. Write a composition of functions that represents the total cost of a riding lawn mower on sale. How much will Mr. Rivera pay for a riding lawn mower that has a marked price of $3000?
Solution:
a) Let x represent the marked price and p(x) represent the price after discount. Since a discount of 15% is given, the price would be:
p(x) = 
b) If x = discounted price and t(x) = total cost with sales tax, then:
t(x) = 
c) Let t(x) represents the total cost with sales tax
![t[p(x)] =p(x)+6.5\%\ of\ p(x) \\\\t[p(x)] = 0.85x+(0.065*0.85x)\\\\t[p(x)] =0.90525x\\\\for\ x=\$3000:\\\\t[p(3000)] = 0.90525*3000=\$2715.75](https://tex.z-dn.net/?f=t%5Bp%28x%29%5D%20%3Dp%28x%29%2B6.5%5C%25%5C%20of%5C%20p%28x%29%20%5C%5C%5C%5Ct%5Bp%28x%29%5D%20%3D%200.85x%2B%280.065%2A0.85x%29%5C%5C%5C%5Ct%5Bp%28x%29%5D%20%3D0.90525x%5C%5C%5C%5Cfor%5C%20x%3D%5C%243000%3A%5C%5C%5C%5Ct%5Bp%283000%29%5D%20%3D%200.90525%2A3000%3D%5C%242715.75)
Answer:
3
Step-by-step explanation:
15v-55=-10
15v=45/÷15
v=3
it is to invest in the amount of supply you have and amount of money you earn. making the best out of what you got.
Answer:
Approximately 23,433 children will have cancer.
Step-by-step explanation:
3/1500 can be simplified to 1/500, which can also be written as 0.002. To find the number of children who have cancer, we do 11,721,722 * 0.002, which gives us 23,433.444 which we can round to 23,433.
Answer:
Mean of sampling distribution = 5.10 alcoholic drinks per week
Standard deviation of the sampling distribution = 0.11
Step-by-step explanation:
We are given the following in the question:
Mean, μ = 5.10 alcoholic drinks per week
Standard Deviation, σ = 1.3401
Sample size, n = 150
a) Mean of sampling distribution
The best approximator for the mean of the sampling distribution is the population mean itself.
Thus, we can write:
b) Standard deviation of the sampling distribution
