Answer:
Step-by-step explanation:
2^0 is less than or equal to 1!, because 1<= 1
if 2^n <= (n+1)!, we wish to show that 2^(n+1) <= (n+2)!, since
(n+2)! = (n+1)! * (n+2), and (n+1)!>= 2^n, then we want to prove that n+2<=2, which is always true for n>=0
Here's how one would solve it:
17 + 3x2 = 6x
17 + 6 = 6x
23 = 6x
x = 23/6
There's only one solution.
The series 1022,1032,1042,1052....
a1=a=1022
d=a2-a1=1032-1022=10
n=5 as 5th term
Sn= a+(n-1)d
= 1022+(5-1)10
= 1022+40
= 1062
Next house will have 1062 as number.