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marshall27 [118]

3 years ago

10

Determine whether 4x + 15 + x is equivalent to 5(3 + x). Complete the sentence to justify your answer. Applying the to 5(3 + x),

you get 15 + 5x. 5x is equivalent to x + x. Therefore, 4x + 15 + x is to 5(3 + x).

1 answer:

Helga [31]3 years ago

4 0

71 is because ishainebap. Sksodjehxhx

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Emily drew a scale drawing of a house and its lot. The back patio is 42 millimeters long in the drawing. The actual patio is 27

kirill [66]

the scale factor used in Emily scale drawing is K = 1.63 mm/m

<h3>What scale did Emily use?</h3>

We know that Emily drew a scale drawing of a house and its lot.

In the scale drawing, the back patio is 42 millimeters long, and we know that the actual patio is 27 meters long.

Then the scale relates the measures 44mm and 27 meters, such that if the scale is K, we can write:

K*27m = 44mm

Solving for K, we can write:

K = (44/27) mm/m = 1.63 mm/m

So the scale factor used in Emily's scale drawing is K = 1.63 mm/m

If you want to learn more about scale factors:

brainly.com/question/25722260

#SPJ1

5 0

2 years ago

Jose wants to build a rectangular kennel for his dog. His dad will let him use a spot in the corner of the yard that is 12 feet

Varvara68 [4.7K]

The answer is 42 ft 4 in

The perimeter of a rectangle with length l and width w is:
P = 2l + 2w

l = 12 ft 3 in
w = 8 ft 11 in

1 ft = 12 in
l = 12 * 12 in + 3 in = 144 in + 3 in = 147 in
w = 8 * 12 in + 11 in = 96 in + 11 in = 107 in

P = 2 * 147 + 2 * 107 = 294 + 214 = 508 in
P = 508 in = 504 in + 4 in = 42 * 12 in + 4 in = 42 ft 4 in

7 0

4 years ago

Last month rudys tacos sold 22 dinner specials. The next month they sold 250% of last months dinners. How many dinner specials d

vlabodo [156]

Answer:

55 special dinners

Step-by-step explanation:

From the question,

Last month rudys tacos sold 22 dinner specials.

The next month they sold 250% of last months dinners.

Hence:

250% × 22 special dinners

= 55 special dinners

The number of dinner specials they sold this month is 55 special dinners

4 0

3 years ago

Identify the standard form of the equation by completing the square.

OLEGan [10]

Answer:

$\dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1$

Step-by-step explanation:

<u>Given equation</u>:

$4x^2-9y^2-8x+36y-68=0$

This is an equation for a horizontal hyperbola.

<u>To complete the square for a hyperbola</u>

Arrange the equation so all the terms with variables are on the left side and the constant is on the right side.

$\implies 4x^2-8x-9y^2+36y=68$

Factor out the coefficient of the x² term and the y² term.

$\implies 4(x^2-2x)-9(y^2-4y)=68$

Add the square of half the coefficient of x and y inside the parentheses of the left side, and add the distributed values to the right side:

$\implies 4\left(x^2-2x+\left(\dfrac{-2}{2}\right)^2\right)-9\left(y^2-4y+\left(\dfrac{-4}{2}\right)^2\right)=68+4\left(\dfrac{-2}{2}\right)^2-9\left(\dfrac{-4}{2}\right)^2$

$\implies 4\left(x^2-2x+1\right)-9\left(y^2-4y+4\right)=36$

Factor the two perfect trinomials on the left side:

$\implies 4(x-1)^2-9(y-2)^2=36$

Divide both sides by the number of the right side so the right side equals 1:

$\implies \dfrac{4(x-1)^2}{36}-\dfrac{9(y-2)^2}{36}=\dfrac{36}{36}$

Simplify:

$\implies \dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1$

Therefore, this is the standard equation for a horizontal hyperbola with:

center = (1, 2)
vertices = (-2, 2) and (4, 2)
co-vertices = (1, 0) and (1, 4)
$\textsf{Asymptotes}: \quad y = -\dfrac{2}{3}x+\dfrac{8}{3} \textsf{ and }y=\dfrac{2}{3}x+\dfrac{4}{3}$
$\textsf{Foci}: \quad (1-\sqrt{13}, 2) \textsf{ and }(1+\sqrt{13}, 2)$

4 0

2 years ago

PLSSSSS HELP I WILL GIVE BRAINLIEST TO CORRECT ANSWER

Luba_88 [7]

A: 49

B:45

C: 20.1

D:114

(3x-11)+(6x-10)+x=180

10x-21=180

10x=201

x=20.1

(I think I did that right)

8 0

3 years ago