we can conclude that the last digit of the product of all the numbers between 11 and 29 is 0.
<h3>What is the last digit of the product of all the numbers between 11 and 29?</h3>
Here we want to find the last digit of the product between all the whole numbers larger than 11 and smaller than 29.
Then we have the product:
P = 12*13*14*15*16*17*18*19*20*21*22*23*24*25*26*27*28
Now, notice that there is a 20 there.
Any number times 20 will end with a zero, then:
P = 20*(12*13*14*15*16*17*18*19*21*22*23*24*25*26*27*28)
Only with that, we can conclude that the last digit of the product of all the numbers between 11 and 29 is 0.
If you want to learn more about products:
brainly.com/question/10873737
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Answer:
X is 64.
Step-by-step explanation:
64/4 = 16
16-3 =13
13 is greater than or equal to 13
Hope this helps!
Answer:
7680
Step-by-step explanation:
16(24)20
7680
The answer to your question is 2.47
