A could be 2 while B could be 3, so -2a+3b turns into -4+9, which equals 5.
From what I know you can't really solve a a single equation with two-variables so it's just a matter of trial and error.
Just try plugging in a small number like 2 for a just to try it and you get 8b^2=72.
Divide everything by 8 to isolate b and you get that b^2=9.
Square root everything and you'll find that b=3. This is just one possible combination, I'm sure there are many more but this is obviously the one that was intended to be found.
Now that we know that a=2 and b=3 just plug them into the equation.
-2(2)+3(3)=?
-4+9=?
5
Sorry about having to use this ^ symbol, the equation maker is not working.
Answer:
(-10,-4)
Step-by-step explanation:
The point is moved to the other side of the y axis.
The y coordinate would stay the same and the x coordinate would move the same number of units but on the opposite side (that's why its -10).
Answer:
Let's name the digit:
x- ones digit
y - tens digit
we know that x=y-2.
Now, y can be 6,7,8,9 (the number is between 60 and 100 (so depending on your understanding of "between", 0 is also possible. but then the number would have to have -2 as its ones digit, so in any case, it's not possible).
So the possibilities with x=y-2:
64
75
86
97
Out of those 64 and 86 are even, so they can't be prime.
75 has 5 in its ones number: it's divisible by 5.
so the correct answer is 97.
Step-by-step explanation:
Hope this helps!
A line graph? I don't understand the question as much but a line graph would do if thats what ur looking for
Hope this is somehow helpful!
