The width is 3 and the height is 3
Answer:
PΔJKL=66
Step-by-step explanation:
so we are given the line segments JK, KL, and LJ which are tangent to k(O), and also that JA=9, AL=10, and CK=14
JL=JA+AL (parts whole postulate)
JL=9+10=19 (substitution, algebra)
JA=JB=9 (tangent segments from the same point are congruent)
CK=KB=14 (tangent segments from the same point are congruent)
JK=JB+KB (parts whole postulate)
JK=9+14=23 (substitution, algebra)
LA=LC=10 (tangent segments from the same point are congruent)
LK=LC+CK (parts whole postulate)
LK=10+14=24 (substitution, algebra)
Perimeter of ΔJKL=LK+KL+LJ (perimeter formula for triangles)
Perimeter of ΔJKL=23+24+19=66 (substitution, algebra)
Answer:
175 minutes or 2 hours 55 minutes
Step-by-step explanation:
do 25 times 7
Answer:
you would have to multiply and Keep change flip keep the 9/4 change the division to miltiplication and flip -3/4 to 4/-3 then u slove
9/4 * 4/-3
Step-by-step explanation:
(f+g)(x) = 8x+2
(f-g)(x) = 4x-6
Step-by-step explanation:
Given
we have to find
<u>a. (f+g)(x)</u>
<u>b. (f-g)(x)</u>
Hence,
(f+g)(x) = 8x+2
(f-g)(x) = 4x-6
Keywords: Functions, Operations on Functions
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