Answer: 0.067 litres of water
Step-by-step explanation:
The mode is:
Concentration of new solution = Moles of acid in original solution / (Volume of original solution + Volume of water added)
Assume volume of water added is w.
12 = 16 (0.2) / (0.2 + w)
(0.2 + w) * 12 = 3.2
0.2 + w = 3.2 / 12
w = (3.2 / 12) - 0.2
w = 0.067 litres of water
Answer:
Step-by-step explanation:
Answer:
<em>The probability that code is 
will be 
</em>
Step-by-step explanation:
From 00 to 49, there are total 50 two-digit numbers.
The total number of alphabets is 26.
So, the probability of choosing 14 from all 50 two digit numbers will be: 
and the probability of choosing '
' from all 26 alphabets will be: 
Thus, the probability that code is is 
4.for every minute you walk 30 feet
5. Minutes
6.distance
7.just put 1 on the x axis and 30 on the y axis so the coordinate pair would be (1,30) and do the same for the rest (3, 90) (5,150) and (7,210)
Answer:
Roots are not real
Step-by-step explanation:
To prove : The roots of x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0 are real for all real values of k ?
Solution :
The roots are real when discriminant is greater than equal to zero.
i.e. b^2-4ac\geq 0b
2
−4ac≥0
The quadratic equation x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0
Here, a=1, b=1-k and c=k-3
Substitute the values,
We find the discriminant,
D=(1-k)^2-4(1)(k-3)D=(1−k)
2
−4(1)(k−3)
D=1+k^2-2k-4k+12D=1+k
2
−2k−4k+12
D=k^2-6k+13D=k
2
−6k+13
D=(k-(3+2i))(k+(3+2i))D=(k−(3+2i))(k+(3+2i))
For roots to be real, D ≥ 0
But the roots are imaginary therefore the roots of the given equation are not real for any value of k.
