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3 years ago

When graphing inequalities, where can the solutions be found?

Mathematics

2 answers:

quester [9]3 years ago

8 0

Answer:

Took the quiz. Answer is letter C."Where the shading overlaps."

Step-by-step explanation:

Hope this helps.

Hitman42 [59]3 years ago

3 0

Solutions will be located in the shaded region. Since this is a “less than” problem, ordered pairs on the boundary line are not included in the solution set. These values are located in the shaded region, so are solutions. (When substituted into the inequality x–y<3.

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The dimensions of a rectangle porch are 16 feet long 12 feet wide. Use the scale of 1 inch=4 feet and a ruler to make a scale dr

Mnenie [13.5K]

Answer:

4 inch long and 3 inch wide

Step-by-step explanation:

so since the scale factor is 1 inch = 4 feet and the actual length is 16 feet by 12 feet all you got to do is divide both lengths by 4 and you get 4 and 3 and you convert the unit to inches so it would be 4 inches and 3 inches. now all you got to do is draw a 4 inch long by 3 inch wide rectangle and your good

3 0

3 years ago

Read 2 more answers

6(2 + x) = 12 + 6x illustrates what property of multiplication?

ElenaW [278]

This equatuon illustrates <span>distributive of multiplicatiton over addition.
</span><span>
If we have a set E with two relation * and + : (E,+,*) we say that the relation * is distributive with respect to the relation
If a*(b+c) = a*b + a*c for every a,b,c from E</span>

5 0

3 years ago

Is 12a-a simplified?

7nadin3 [17]

12a−a

=12a−1a

=12a+−1a

=a+a+a+a+a+a+a+a+a+a+a+a+−a

=a+a+a+a+a+a+a+a+a+a+a

=11a

5 0

4 years ago

The area of a square is 64n^36 units. What is the side length of one side of the square?

CaHeK987 [17]

√64= 8
√n³⁶= n¹⁸

Final answer: 8n¹⁸, or B
Remember that (n¹⁸)²= n³⁶. Therefore n⁶ is incorrect.

4 0

3 years ago

Read 2 more answers

It is believed that Lake Tahoe Community College (LTCC) Intermediate Algebra students get less than seven hours of sleep per nig

Kitty [74]

Answer: No , at 0.05 level of significance , we have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

Step-by-step explanation:

Let $\mu$ denotes the average hours of sleep per night.

As per given , we have

$H_0:\mu=7\\H_a:\mu$

, since $H_a$ is left-tailed and population standard deviation is unknown, so the test is a left-tailed t -test.

Also , it is given that ,

Sample size : n= 22

Sample mean : $\overline{x}=7.24$

Sample standard deviation : s= 1.93

Test statistic : $t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}$

i.e. $t=\dfrac{7.24-7}{\dfrac{1.93}{\sqrt{22}}}\approx0.58$

For significance level $\alpha=0.05$ and degree of freedom 21 (df=n-1),

Critical t-value for left-tailed test= $t_{\alpha, df}=t_{0.05,21}=- 1.7207$

Decision : Since the test statistic value (0.58) > critical value 1.7207, it means we are failed to reject the null hypothesis .

[Note : When $|t_{cal}|>|t_{cri}|$ , then we accept the null hypothesis.]

Conclusion: We have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

6 0

3 years ago