Question

Need Help Please, This One Is A Bit Difficult.

Answer 1

Answer: 432 units²

Step-by-step explanation:

The figure is composed by two trapezoids.

The formula for calculate the area of a trapezoid is:

$A=\frac{h}{2}(B+b)$

Where "B" is the larger base, "b" is the smaller base and "h" is the height.

Let be $A_f$ the area of the figure, $A_1$ the area of the trapezoid on the left and $A_2$ the area of the trapezoid of the right. Then the area of the figure will be:

 $A_f=A_1+A_2$

$A_f=\frac{h_1}{2}(B_1+b_1)+\frac{h_2}{2}(B_2+b_2)$

Substituting values, you get:

$A_f=\frac{16units}{2}(25units+4units)+\frac{10units}{2}(25units+15units)=432units^2$

Answer 2

Answer:

Area of given figure = 432 unit ²

Step-by-step explanation:

Points to remember

Area of trapezoid = h(a + b)/2

Where h - height  and a and b  are two parallel sides

To find the area of given figure

It is given two trapezoid

Area of 1st trapezoid

h = 16, a = 25 and b = 4

Area = h(a+ b)/2

 = 16(25 + 4)/2

 = 232 units ²

Area of 2nd trapezoid

h = 10, a = 25 and b = 15

Area = h(a+ b)/2

 = 10(25 + 15)/2

 = 200 units ²

Total area = 232 + 200 = 432 units²