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Advocard [28]
3 years ago
8

3^(x−1) = 27 please and thank you in advance

Mathematics
2 answers:
Nezavi [6.7K]3 years ago
7 0

Answer: x=10

Step-by-step explanation:

Basically you will first have to 3^(x-1). It's just x-1 but repeated 3 times:

x-1+x-1+x-1=27 now, combine like terms:

x+x+x-1-1-1=27 ---> 3x-3=27 Get 3x by itself by adding 3 to -3 and 27:

3x-3+3=27+3

3x=30 Now Divide.

3x/3=30/3

x=10

notka56 [123]3 years ago
3 0

Answer: x = 4

Step-by-step explanation:

Given :

3^{x-1} = 27

27 can also be written in index form , so the equation becomes

3^{x-1} = 3^{3}

since they have the same base , we will equate their power , that is

x - 1 = 3

x = 4

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Simon has more money than Kande. if Simon gave Kande K20, they would have the same amount. While if Kande gave Simon $22, Simon
motikmotik

Given parameters;

  Let us solve this problem step by step;

Let us represent Simon's money by S

Kande's money by K

  • Simon has more money than Kande

               S > K

  •  if Simon gave Kande K20, they would have the same amount;

 if Simon gives $20, his money will be  S - 20 lesser;

      When Kande receives $20, his money will increase to K + 20

                     S - 20  = K + 20   ------ (i)

  • While if Kande gave Simon $22, Simon would then have twice as much as Kande;

          if Kande gave Simon $22, his money will be K - 22

    Simon's money, S + 22;

                  S + 22  = 2(K - 22)    ------ (ii)

Now we have set up two equations, let us solve;

         S - 20  = K + 20  ---- i

         S + 22  = 2(K - 22)  ;       S + 22  = 2K - 44  ---- ii

So,      S - 20  = K + 20

          S + 22  = 2K - 44

subtract both equations;

               -20 - 22  = (k -2k)  + 64

                   -42  = -k + 64

                       k  = 106

Using equation i, let us find S;

            S - 20 = K + 20

             S - 20  = 106 + 20

              S = 106 + 20 + 20  = 146

Therefore, Kande has $106 and Simon has $146

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Answer:

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Step-by-step explanation:

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