Answer:
![P(Cable\ TV\ only) = 50\%](https://tex.z-dn.net/?f=P%28Cable%5C%20TV%5C%20only%29%20%3D%2050%5C%25)
![P(Internet\ |\ cable\ TV) = 31.25\%](https://tex.z-dn.net/?f=P%28Internet%5C%20%7C%5C%20cable%5C%20TV%29%20%3D%2031.25%5C%25)
![P(exactly\ 2\ services) = 23\%](https://tex.z-dn.net/?f=P%28exactly%5C%202%5C%20services%29%20%3D%2023%5C%25)
![P(Internet\ and\ cable\ TV \only) = 23\%](https://tex.z-dn.net/?f=P%28Internet%5C%20and%5C%20cable%5C%20TV%20%5Conly%29%20%3D%2023%5C%25)
Step-by-step explanation:
Given
![Cable\ TV = 80\%](https://tex.z-dn.net/?f=Cable%5C%20TV%20%3D%2080%5C%25)
![Internet = 44\%](https://tex.z-dn.net/?f=Internet%20%3D%2044%5C%25)
![Telephone = 29\%](https://tex.z-dn.net/?f=Telephone%20%3D%2029%5C%25)
![Cable\ TV\ and\ Internet = 25\%](https://tex.z-dn.net/?f=Cable%5C%20TV%5C%20and%5C%20Internet%20%3D%2025%5C%25)
![Cable\ TV\ and\ Telephone = 20\%](https://tex.z-dn.net/?f=Cable%5C%20TV%5C%20and%5C%20Telephone%20%3D%2020%5C%25)
![Internet\ and\ Telephone = 23\%](https://tex.z-dn.net/?f=Internet%5C%20and%5C%20Telephone%20%3D%2023%5C%25)
![All\ Services = 15\%](https://tex.z-dn.net/?f=All%5C%20Services%20%3D%2015%5C%25)
Solving (a): A) P(cable TV only).
First, we calculate n(cable TV only)
This is calculated as:
![n(cable\ TV\ only) = (Cable\ TV) - (Cable\ TV\ and\ Internet) - (Cable\ TV\ and\ Telephone) + (All\ Services)](https://tex.z-dn.net/?f=n%28cable%5C%20TV%5C%20only%29%20%3D%20%28Cable%5C%20TV%29%20-%20%28Cable%5C%20TV%5C%20and%5C%20Internet%29%20-%20%28Cable%5C%20TV%5C%20and%5C%20Telephone%29%20%2B%20%28All%5C%20Services%29)
![n(cable\ TV\ only) = 80\% - 25\% - 20\% + 15\%](https://tex.z-dn.net/?f=n%28cable%5C%20TV%5C%20only%29%20%3D%2080%5C%25%20-%2025%5C%25%20-%2020%5C%25%20%2B%2015%5C%25)
![n(cable\ TV\ only) = 50\%](https://tex.z-dn.net/?f=n%28cable%5C%20TV%5C%20only%29%20%3D%2050%5C%25)
The probability is:
![P(Cable\ TV\ only) = \frac{n(Cable\ TV\ only)}{100\%}](https://tex.z-dn.net/?f=P%28Cable%5C%20TV%5C%20only%29%20%3D%20%5Cfrac%7Bn%28Cable%5C%20TV%5C%20only%29%7D%7B100%5C%25%7D)
![P(Cable\ TV\ only) = \frac{50\%}{100\%}](https://tex.z-dn.net/?f=P%28Cable%5C%20TV%5C%20only%29%20%3D%20%5Cfrac%7B50%5C%25%7D%7B100%5C%25%7D)
![P(Cable\ TV\ only) = 50\%](https://tex.z-dn.net/?f=P%28Cable%5C%20TV%5C%20only%29%20%3D%2050%5C%25)
Solving (b): P(Internet | cable TV).
This is calculated as:
![P(Internet\ |\ cable\ TV) = \frac{Cable\ TV\ and\ Internet}{Cable\ TV}](https://tex.z-dn.net/?f=P%28Internet%5C%20%7C%5C%20cable%5C%20TV%29%20%3D%20%5Cfrac%7BCable%5C%20TV%5C%20and%5C%20Internet%7D%7BCable%5C%20TV%7D)
![P(Internet\ |\ cable\ TV) = \frac{25\%}{80\%}](https://tex.z-dn.net/?f=P%28Internet%5C%20%7C%5C%20cable%5C%20TV%29%20%3D%20%5Cfrac%7B25%5C%25%7D%7B80%5C%25%7D)
![P(Internet\ |\ cable\ TV) = \frac{25}{80}](https://tex.z-dn.net/?f=P%28Internet%5C%20%7C%5C%20cable%5C%20TV%29%20%3D%20%5Cfrac%7B25%7D%7B80%7D)
![P(Internet\ |\ cable\ TV) = 31.25\%](https://tex.z-dn.net/?f=P%28Internet%5C%20%7C%5C%20cable%5C%20TV%29%20%3D%2031.25%5C%25)
Solving (c): P(exactly 2 services).
This is calculated as:
![P(exactly\ 2\ services) = (Cable\ TV\ and\ Internet - All) + (Cable\ TV\ and\ Telephone - All) + (Internet\ and\ Telephone - All)](https://tex.z-dn.net/?f=P%28exactly%5C%202%5C%20services%29%20%3D%20%28Cable%5C%20TV%5C%20and%5C%20Internet%20-%20All%29%20%2B%20%28Cable%5C%20TV%5C%20and%5C%20Telephone%20-%20All%29%20%2B%20%28Internet%5C%20and%5C%20Telephone%20-%20All%29)
![P(exactly\ 2\ services) = (25\% - 15\%) + (20\% - 15\%) + (23\%-15\%)](https://tex.z-dn.net/?f=P%28exactly%5C%202%5C%20services%29%20%3D%20%2825%5C%25%20-%2015%5C%25%29%20%2B%20%2820%5C%25%20-%2015%5C%25%29%20%2B%20%2823%5C%25-15%5C%25%29)
![P(exactly\ 2\ services) = (10\%) + (5\%) + (8\%)](https://tex.z-dn.net/?f=P%28exactly%5C%202%5C%20services%29%20%3D%20%2810%5C%25%29%20%2B%20%285%5C%25%29%20%2B%20%288%5C%25%29)
![P(exactly\ 2\ services) = 23\%](https://tex.z-dn.net/?f=P%28exactly%5C%202%5C%20services%29%20%3D%2023%5C%25)
Solving (d): P(Internet and cable TV only).
This is calculated as:
![P(Internet\ and\ cable\ TV \only) = \frac{(Internet\ and\ cable\ TV \only)}{100\%}](https://tex.z-dn.net/?f=P%28Internet%5C%20and%5C%20cable%5C%20TV%20%5Conly%29%20%3D%20%5Cfrac%7B%28Internet%5C%20and%5C%20cable%5C%20TV%20%5Conly%29%7D%7B100%5C%25%7D)
![P(Internet\ and\ cable\ TV \only) = \frac{23\%}{100\%}](https://tex.z-dn.net/?f=P%28Internet%5C%20and%5C%20cable%5C%20TV%20%5Conly%29%20%3D%20%5Cfrac%7B23%5C%25%7D%7B100%5C%25%7D)
![P(Internet\ and\ cable\ TV \only) = \frac{23\%}{1}](https://tex.z-dn.net/?f=P%28Internet%5C%20and%5C%20cable%5C%20TV%20%5Conly%29%20%3D%20%5Cfrac%7B23%5C%25%7D%7B1%7D)
![P(Internet\ and\ cable\ TV \only) = 23\%](https://tex.z-dn.net/?f=P%28Internet%5C%20and%5C%20cable%5C%20TV%20%5Conly%29%20%3D%2023%5C%25)
Answer:
2nd one
Step-by-step explanation:
9514 1404 393
Answer:
(b) a trapezoid
Step-by-step explanation:
A graph of the points reveals one pair of parallel sides: a trapezoid.
Answer:
Option c) 2 is the answer
Step-by-step explanation:
using standard deviation formulae