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Wewaii [24]
3 years ago
8

The school band collected $2,892 for 480 tickets sold to their spring concert. Adult tickets were $8 each and student tickets we

re $5 each. How many adult tickets were sold? Write and equation. This is an Algebra I question!!!
Mathematics
1 answer:
Elanso [62]3 years ago
3 0

Answer:

164 tickets

Step-by-step explanation:

We can denote number of adult tickets as "y"

Then if number of adult tickets is "y" then number of student tickets can be expressed as (480-y)

We were given Total cost of tickets as ($2892) ............eqn(1) and the cost of adult ticket is $8 per one, and also Cost student ticket $5 per one

the algebra equation can be expressed as :

8y + 5y= 2892

If we substitute eqn (1) we have

8y + 5(480 - y) = 2892

8a + 2400 - 5y = 2892

2892 - 2400= 8y-5y

492=3y

y = 164

Therefore, the number of adult tickets sold is 164

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nignag [31]
Standard reduction of order procedure: suppose there is a second solution of the form y_2(x)=v(x)y_1(x), which has derivatives

y_2=vx^4
{y_2}'=v'x^4+4vx^3
{y_2}''=v''x^4+8v'x^3+12vx^2

Substitute these terms into the ODE:

x^2(v''x^4+8v'x^3+12vx^2)-7x(v'x^4+4vx^3)+16vx^4=0
v''x^6+8v'x^5+12vx^4-7v'x^5-28vx^4+16vx^4=0
v''x^6+v'x^5=0

and replacing v'=w, we have an ODE linear in w:

w'x^6+wx^5=0

Divide both sides by x^5, giving

w'x+w=0

and noting that the left hand side is a derivative of a product, namely

\dfrac{\mathrm d}{\mathrm dx}[wx]=0

we can then integrate both sides to obtain

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v'=\dfrac{C_1}x
v=C_1\ln|x|+C_2

Now

y=C_1x^4\ln|x|+C_2x^4

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3 years ago
Please answer/fix these questions
Mamont248 [21]
Honestly I can’t remember the last time I had to deal with arcs in school, but the answer to the second one is 63 because all triangles add up to 180 degrees and 46+71= 117. 180-117=63
6 0
2 years ago
Eric had a total of 40 nickels and dimes if the total value of the coins is 330 cents, how many nickels and dimes does he have?
kumpel [21]

Answer:

165 of nickels and 165 of dimes

7 0
3 years ago
PLEASEEEE PLEASEEEEEEEEE HELPPPPPPPPPP<br> how do i solve this equation?
Stells [14]

Answer:

360

Step-by-step explanation:

using the definition

n P_{r} = \frac{n!}{(n-r)!}

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then

6P_{4}

= \frac{6!}{(6-4)!}

= \frac{6!}{2!}

= \frac{6(5)(4)(3(2)(1)}{2(1)} ← cancel 2(1) on numerator / denominator

=  6 × 5 × 4 × 3

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7 0
2 years ago
How do you do this with decimals
ICE Princess25 [194]
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Steps:

This is an isosceles triangle which mean 2 angles and 2 sides are congruent. In this case, the 3.3 sides corresponds to the 39 degree angle. This means that the other angle next to x angle is also 39 degrees.

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All the angles in the triangle needs to equal 180.

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3 0
3 years ago
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