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Vsevolod [243]
3 years ago
10

Someone help please

Mathematics
1 answer:
ki77a [65]3 years ago
3 0

Answer:

A to #4

B to #3

C to #1

D to #2

Step-by-step explanation:

A. 7 + 3² = 16

B. 5 - 2²=1

C. 2 · 2³ = 2^4

D. 3^4/3^1=27

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What is the slope of this graph?<br> 0.3<br> -3<br> los<br> 1<br> 3<br> 3<br> 1<br> 2 3 4 5
iren2701 [21]

Answer:

A

Step-by-step explanation:

Use the formula rise/run. The rise, in this case, was 3 and the run was 1. There for it would be 3/1 which is simplified to 3.

3 0
3 years ago
A can of soda weighs 336 grams. Find the weight in kilograms of 15 cans.
zaharov [31]

Answer:

5.04

Step-by-step explanation:

1 can equals to 336 grams

so 15 cans will equal to 336 X 15

which is 5040grams

now covert it into kg by dividing it by 1000

which 5.04

4 0
3 years ago
How do you find the unknown?
Anettt [7]
Measure the angle with a protractor
5 0
4 years ago
PLS HELP WILL MARK BRAINIEST!!!! TY
Akimi4 [234]

Answer:

it's "vertical angles and linear pair theorem"

Step-by-step explanation:

8 0
3 years ago
A fire station is to be located along a road of length A, A &lt; q. If fires occur at points uniformly chosen on (0, A), where s
Shtirlitz [24]

Answer:

Step-by-step explanation:

Given that X is uniform in the interval (0,A)

X is continuous since it represents the distance

A fire station is to be located along a road of length A, A < q. If fires occur at points uniformly chosen on (0, A), we  should find where the station be located so as to minimize the expected distance from the fire

Distance can be taken as absolute values here as either side is the same.

E(|x-a|] is to be minimum

E(|x-a|)=E(x-a) for 0<x<a

         =E(a-x), for a<x<A

Using integral we find this value

E(|x-a|)=\int\limits^a_0 {x-a} \, dx +=\int\limits^A_a -{x-a} \, dx\\f(a)=\frac{a^2}{2} -\frac{(A-a)^2}{2}

f(a)=\frac{a^2}{2} +\frac{(A-a)^2}{2} \\f'(a) = a-(A-a)\\f"(a) =2

Using calculus we find that f" is positive so when f' =0 we get solution

f'(a) =0 gives

a=\frac{A}{2}

Hence fire station to be located at the mid point of 0 and A

8 0
4 years ago
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