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Sergeeva-Olga [200]
3 years ago
6

Choose the system of equations which matches the following graph: (5 points) a line includes points 0 comma 0 and negative 1 com

ma 2. A line includes points 2 comma 3 and 1 comma negative 2 Question 12 options: 1) 5x − y = 7 2x − y = 0 2) 5x − y = 7 2x + y = 0 3) 5x + y = −7 2x + y = 0 4) 5x + y = −7 2x − y = 0 Save
Mathematics
1 answer:
IrinaK [193]3 years ago
5 0
(0,0),(-1,2)
slope = (2 - 0) / (-1 - 0) = - 2/1 = -2

so this equation, since it goes thru the origin, is : y = -2x or 2x + y = 0

(2,3),(1,-2)
slope = (-2 - 3) / (1 - 2) = -5/-1 = 5

y = mx + b
slope(m) = 5
(2,3)...x = 2 and y = 3
now sub into the formula and find b, the y int
3 = 5(2) + b
3 = 10 + b
3 - 10 = b
-7 = b
so this equation is : y = 5x - 7 or 5x - y = 7

so ur 2 equations are :
2x + y = 0
5x - y = 7

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  84? Not sure but pretty sure

Step-by-step explanation:

In a straight line, the word can only be spelled on the diagonals, and there are only two diagonals in each direction that have 2 O's.

If 90° and reflex turns are allowed, then the number substantially increases.

Corner R: can only go to the adjacent diagonal O, and from there to one other O, then to any of the 3 M's, for a total of 3 paths.

2nd R from the left: can go to either of two O's, one of which is the same corner O as above. So it has the same 3 paths. The center O can go to any of 4 Os that are adjacent to an M, for a total of 10 more paths. That's 13 paths from the 2nd R.

Middle R can go the three O's on the adjacent row, so can access the three paths available from each corner O along with the 10 paths available from the center O, for a total of 16 paths.

Then paths accessible from the top row of R's are 3 +10 +16 +10 +3 = 42 paths. There are two such rows of R's so a total of 84 paths.

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In fig if x+y=w+z then prove that AOB is a line.​
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As Given, x+y=w+z

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(linear pair.)

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∣ Angles around a point.

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