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AfilCa [17]
2 years ago
13

Ummmm HELP WILL GIVE BRAINLIEST

Mathematics
2 answers:
Deffense [45]2 years ago
8 0

The answer is A......................................

lawyer [7]2 years ago
5 0

Answer:

its B

Step-by-step explanation:

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Subtract. Simplify, if possible.<br> 5/8<br> -<br> * 2 1 / 2 - 3
Nat2105 [25]

2\frac{1}{2} - \frac{5}{8}

Convert the mixed number to an improper fraction:

\frac{5}{2} - \frac{5}{8}

Subtract the fractions to get your final answer:

\frac{15}{8}

8 0
2 years ago
if the total value of the coins is 71$ and she has 9 rolls of dimes, how many rolls of nickels does she have?
Zanzabum

Answer:

18 rolls of nickles

Step-by-step explanation:

One roll of dimes would be the same value as 2 rolls of nickles. If she has 9 rolls of dimes, she would have 18 rolls of nickles.

Dont forget to thanks and rate!

4 0
3 years ago
I am having trouble with this question. ​
a_sh-v [17]

Answer:

x=12√2

y=45°

Step-by-step explanation:

as we know diagonal of a square

=a√2

=12√2

and

y=45°

8 0
2 years ago
Roderick is counting the change on his dresser. he has twice as many pennies as he does dimes. he has twice the amount of dimes
melamori03 [73]
P = 2d
d = 2n.....n = 1/2d
q = d - 3

since dimes is mentioned in relation to  quarters, pennies, and the nickels, u would use d as ur variable

ur expression would be : d + (2d) + (1/2d) + (d - 3) = total amount of coins...then u would solve for d, the number of dimes. And once u know that, u can sub that answer back into ur original equations to find the number of pennies, quarters and nickels
8 0
3 years ago
The magnitude and direction of two vectors are shown in the diagram. What is the magnitude of their sum? ​
VLD [36.1K]

Separate the vectors into their <em>x</em>- and <em>y</em>-components. Let <em>u</em> be the vector on the right and <em>v</em> the vector on the left, so that

<em>u</em> = 4 cos(45°) <em>x</em> + 4 sin(45°) <em>y</em>

<em>v</em> = 2 cos(135°) <em>x</em> + 2 sin(135°) <em>y</em>

where <em>x</em> and <em>y</em> denote the unit vectors in the <em>x</em> and <em>y</em> directions.

Then the sum is

<em>u</em> + <em>v</em> = (4 cos(45°) + 2 cos(135°)) <em>x</em> + (4 sin(45°) + 2 sin(135°)) <em>y</em>

and its magnitude is

||<em>u</em> + <em>v</em>|| = √((4 cos(45°) + 2 cos(135°))² + (4 sin(45°) + 2 sin(135°))²)

… = √(16 cos²(45°) + 16 cos(45°) cos(135°) + 4 cos²(135°) + 16 sin²(45°) + 16 sin(45°) sin(135°) + 4 sin²(135°))

… = √(16 (cos²(45°) + sin²(45°)) + 16 (cos(45°) cos(135°) + sin(45°) sin(135°)) + 4 (cos²(135°) + sin²(135°)))

… = √(16 + 16 cos(135° - 45°) + 4)

… = √(20 + 16 cos(90°))

… = √20 = 2√5

5 0
2 years ago
Read 2 more answers
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