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3 years ago

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Consider the equation 5x-2y=3. If possible, find a second linear equation to create a system of equations that has: Exactly one

solution Exactly two solutions No solutions Infinitely many solutions

2 answers:

nekit [7.7K]3 years ago

4 0

A) One solution: 5x +2y = 0 . . . . (any line with a different slope)

b) Two solutions: not possible

c) No solutions: 5x -2y = 0 . . . . (any different line with the same slope)

d) Infinitely many solutions: 10x -4y = 6 . . . . (any other equation for the same line)

GenaCL600 [577]3 years ago

3 0

Answer with explanation:

1.⇒ The given equation is

5x-2y=3

For one solution ,you should write linear equation in such a way

ax+by=c, such that

$\frac{5}{a}\neq \frac{-2}{b}\neq \frac{3}{c}$

So, the linear equation will be

→3x+4y=8

You can write many more by yourself.

2.⇒Exactly two solutions

The two lines intersect at only one point.So,there are no such lines which has two point of Intersection.

3.⇒No solutions

It means the two lines will never intersect.

For no solution ,you should write equation of line in such a way

ax+by=c, such that

$\frac{5}{a}=\frac{-2}{b}\neq \frac{3}{c}$

So, the linear equation will be

→10x -4y=15

You can write many more by yourself.

4.⇒Infinitely many solutions

For Infinite number of solution ,you should write linear equation in such a way

ax+by=c, such that

$\frac{5}{a}=\frac{-2}{b}=\frac{3}{c}$

→10x-4y=6

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Answer:

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3 years ago

Read 2 more answers

Let C(n, k) = the number of k-membered subsets of an n-membered set. Find (a) C(6, k) for k = 0,1,2,...,6 (b) C(7, k) for k = 0,

vladimir1956 [14]

Answer:

(a) $C(6,0) = 1$ , $C(6,1) = 6$ , $C(6,2) = 15$ , $C(6,3) = 20$ , $C(6,4) = 15$ , $C(6,5) = 6$ , $C(6,6) = 1$ .

(b) $C(7,0) = 1$ , $C(7,1) = 7$ , $C(7,2) = 21$ , $C(7,3) = 35$ , $C(7,4) = 35$ , $C(7,5) = 21$ , $C(7,6) = 7$ , $C(7,7)=1$ .

Step-by-step explanation:

In this exercise we only need to recall the formula for C(n,k):

$C(n,k) = \frac{n!}{k!(n-k)!}$

where the symbol $n!$ is the factorial and means

$n! = 1\cdot 2\cdot 3\cdot 4\cdtos (n-1)\cdot n$ .

By convention 0!=1. The most important property of the factorial is $n!=(n-1)!\cdot n$ , for example 3!=1*2*3=6.

(a) The explanations to the solutions is just the calculations.

$C(6,0) = \frac{6!}{0!(6-0)!} = \frac{6!}{6!} = 1$

$C(6,1) = \frac{6!}{1!(6-1)!} = \frac{6!}{5!} = \frac{5!\cdot 6}{5!} = 6$

$C(6,2) = \frac{6!}{2!(6-2)!} = \frac{6!}{2\cdot 4!} = \frac{5!\cdot 6}{2\cdot 4!} = \frac{4!\cdot 5\cdot 6}{2\cdot 4!} = \frac{5\cdot 6}{2} = 15$

$C(6,3) = \frac{6!}{3!(6-3)!} = \frac{6!}{3!\cdot 3!} = \frac{5!\cdot 6}{6\cdot 6} = \frac{5!}{6} = \frac{120}{6} = 20$

$C(6,4) = \frac{6!}{4!(6-4)!} = \frac{6!}{4!\cdot 2!} = frac{5!\cdot 6}{2\cdot 4!} = \frac{4!\cdot 5\cdot 6}{2\cdot 4!} = \frac{5\cdot 6}{2} = 15$

$C(6,5) = \frac{6!}{5!(6-5)!} = \frac{6!}{5!} = \frac{5!\cdot 6}{5!} = 6$

$C(6,6) = \frac{6!}{6!(6-6)!} = \frac{6!}{6!} = 1$ .

(b) The explanations to the solutions is just the calculations.

$C(7,0) = \frac{7!}{0!(7-0)!} = \frac{7!}{7!} = 1$

$C(7,1) = \frac{7!}{1!(7-1)!} = \frac{7!}{6!} = \frac{6!\cdot 7}{6!} = 7$

$C(7,2) = \frac{7!}{2!(7-2)!} = \frac{7!}{2\cdot 5!} = \frac{6!\cdot 7}{2\cdot 5!} = \frac{5!\cdot 6\cdot 7}{2\cdot 5!} = \frac{6\cdot 7}{2} = 21$

$C(7,3) = \frac{7!}{3!(7-3)!} = \frac{7!}{3!\cdot 4!} = \frac{6!\cdot 7}{6\cdot 4!} = \frac{5!\cdot 6\cdot 7}{6\cdot 4!} = \frac{120\cdot 7}{24} = 35$

$C(7,4) = \frac{7!}{4!(7-4)!} = \frac{6!\cdot 7}{4!\cdot 3!} = frac{5!\cdot 6\cdot 7}{4!\cdot 6} = \frac{120\cdot 7}{24} = 35$

$C(7,5) = \frac{7!}{5!(7-2)!} = \frac{7!}{5!\cdot 2!} = 21$

$C(7,6) = \frac{7!}{6!(7-6)!} = \frac{7!}{6!} = \frac{6!\cdot 7}{6!} = 7$

$C(7,7) = \frac{7!}{7!(7-7)!} = \frac{7!}{7!} = 1$

For all the calculations just recall that 4! =24 and 5!=120.

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2 years ago

Please help asap! giving brainliest for those who help!!

dsp73

Answer:

I think this is right:

50:50

5/10

0.5

50%

Step-by-step explanation:

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2 years ago

Carly draws quadrilateral JKLM with vertices J(-3,3), K(3,3), L(2,-1),and M(-2, -1). What is the best way to classify the quadri

Trava [24]

Answer:

Trapezoid

Step-by-step explanation:

The points are shown in the attached graph.

<em>You can clearly see from the picture that it is a "Trapezoid".</em>

<em />

<em>Trapezoid</em><em> is basically a quadrilateral (4 sided-figure) that has 1/2 pair of parallel sides.</em>

<em>On the other hand, a </em><em>parallelogram</em><em> has 2 pair of parallel sides.</em>

<em />

Thus, a parallelogram is a special type of trapezoid where there are 2 pair of parallel sides. But trapezoid need not be a parallelogram.

<em>The picture shows 1 pair of parallel sides, hence it is a </em><em>trapezoid.</em>

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2 years ago

Which expression demonstrates the distributive property applied to the expression 4(3 + 7)

GREYUIT [131]

4(3 + 7)

= 4(3) + 4(7) //Demonstrating distributive property

= 12 + 28

= 40

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2 years ago