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kolbaska11 [484]
3 years ago
8

2. Evaluate the expression -4r +5 y-14 when r = 0 and y=- 55

Mathematics
1 answer:
Alecsey [184]3 years ago
3 0

Answer:

Answer is 261

Step-by-step explanation:

-4r+5y-14     r=0    y=55

insert "r" and "y" values into equation

=-4(0)+5(55)-14

evaluate;

-4(0)=0

5(55)=275

so, now the equation would look like this;

=275-14

<h2>=261</h2>
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Andrei [34K]

Answer:

Solution : Option B, or 9π

Step-by-step explanation:

We are given that y = x, x = 3, and y = 0.

Now assume we have a circle that models the given information. The radius will be x, so to determine the area of that circle we have πx². And knowing that x = 3 and y = 0, we have the following integral:

\int _0^3

So our set up for solving this problem, would be such:

\int _0^3x^2\pi \:

By solving this integral we receive our solution:

\int _0^3x^2\pi dx,\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=> \pi \cdot \int _0^3x^2dx\\\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1}\\=> \pi \left[\frac{x^{2+1}}{2+1}\right]^3_0\\=> \pi \left[\frac{x^3}{3}\right]^3_0\\\mathrm{Compute\:the\:boundaries}: \left[\frac{x^3}{3}\right]^3_0=9\\\mathrm{Substitute:9\pi }

As you can tell our solution is option b, 9π. Hope that helps!

5 0
3 years ago
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Step-by-step explanation:


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Answer:

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