Question

When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction

Answer 1

The mass of Calcium carbonate needed : 246 g

Further explanation

Reaction

CaCO₃(s)→CaO(s)+CO₂(g)

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.

Then for 55 L of CO₂, mol :

$\tt \dfrac{55}{22.4}=2.46$

From the equation, mol ratio for mol CaCO₃ : mol CO₂ = 1 : 1, so :

mol CaCO₃ = mol CO₂ = 2.46

mass CaCO₃(MW=100g/mol) :

$\tt mass=mol\times MW\\\\mass=2.46\times 100\\\\mass=246~g$