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anastassius [24]
3 years ago
5

In most cases, the two major climatic factors affecting the distribution of organisms in terrestrial ecosystems are _____. amoun

t of water and temperature predators and parasites temperature and salinity wind and amount of water competitors and predators
Biology
1 answer:
kari74 [83]3 years ago
4 0
In most cases, the two major climatic factors affecting the distribution of organisms in terrestrial ecosystems are the amount of water and temperatures. Terrestrial ecosystems rely on the sun's energy to support the growth and metabolism of the organisms. Plants use the sunlight, then they supply the organisms that are higher up the food chain with energy and the structural buildings blocks of life. Water is also essential for the survival of these organisms.
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Which statement best explains why muscle cells and skin cells do not look and act the same?
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The statement which explains why muscle cells and skin cells do not look and act the same is this: THE GENES IN EACH TYPE OF CELL ARE BEEN EXPRESSED DIFFERENTLY. 
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This would be a recessive disease.

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Mother is Dd (has to be because one child has the disease)

Parents cross is dd x Dd which gives rise to Dd (0.5) and dd (0.5). Each time they have a child they have a 50% chance of the child having the disease. In their case, only one of their 3 children is dd. The others though are carriers!
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In most primate species, males rarely participate in infant care. <br> a. True <br> b. False
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A. males rarely participate in infant care
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This scientist performed an experiment where he weighed a pot with soil and then grew a seedling in it for five years. During th
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A hidden population has been discovered in Turkey. Researchers have calculated that 22% of the population have Uner Tan Syndrome
Rainbow [258]

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Thus, 50% of the population are are heterozygous carriers for this condition

Explanation:

Researchers have calculated that 22% of the population have Uner Tan Syndrome. This condition follows the recessive mode of inheritance.

22% have the condition = q² (genotypic frequency uu) = 22/100 = 0.22

using the formular p + q = 1, since q² = 0.22, q = √0.22 = 0.4690

Thus p = 1-q where  is 0.4690 = 1-0.4690

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Then p² = 0.5310² = 0.2820 = 28% (genotypic frequency of homozygous normal)

using the formula p² + 2pq + q² where 2pq is the genotypic frequency of the heterozygous carriers. Thus, we have

2 x 0.5310 x 0.4690 = 0.498 = 50%

Thus, 50% of the population are are heterozygous carriers for this condition

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