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Law Incorporation [45]
3 years ago
14

Which of the following is an example of a carnivore?

Chemistry
1 answer:
Wittaler [7]3 years ago
6 0

Answer:

D, Lions

Explanation:

Lions are meat eaters, meaning their food and energy requirements derive solely from anima tissue or meat (whether from hunting or scavenging)

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Calculate the mass in grams of 1.72×10^24 molecules of formaldehyde. The chemical formula for formaldehyde is CH2O.
pishuonlain [190]

Answer: m= 85.8 g CH2O

Explanation: First step is convert the molecules of CH2O to moles using the Avogadro's Number.

1.72x10²⁴ molecules CH2O x 1 mole CH2O / 6.022x10²³ molecules CH2O

= 2.86 moles CH2O

Next is convert the moles of CH2O to mass using the molar mass of CH2O

2.86 moles CH2O x 30 g CH2O / 1 mole CH2O

= 85.8 g CH2O

5 0
3 years ago
What is a hypothesis
zmey [24]
<span>A supposition or proposed explanation made on the basis of limited evidence as a starting point for further investigation.</span>
4 0
3 years ago
Read 2 more answers
Mass box A = 10 grams; Mass box B = 5 grams; Mass box C—made of one A and one B Mass ratio A/B =
LUCKY_DIMON [66]

Answer:

mass ratio of A/B is 2:1

Explanation:

Since the mass of box A = 10g

                mass of box B = 5g

   Mass of box C = mass of box A + mass of box

A ratio compares two quantities. To find the ratio of the two boxes:

  Ratio of A to B = \frac{mass of A}{mass of B}

  Ratio of A to B = \frac{10grams}{5grams} = 2

The mass ratio is 2:1 i.e box A has twice the mass of B

8 0
3 years ago
The term for free electrons in metals transferring energy by colliding with other atoms or electrons is _____.
shepuryov [24]
Conduction

In metals, the electrons of each atom are delocalized, which means they are free to move about in the structure of the metal. When heat is applied at one end of the metal, the electrons there are excited and collide with surrounding particles, transferring their energy to them. This is what makes metals very good conductors of both heat and electricity. 
4 0
3 years ago
Read 2 more answers
When a 5.00-g metal piece, A, was immersed in 38.0 mL of water, the water level rose to 50.0 mL. Similarly, when a 5.00-g metal
Mnenie [13.5K]

Answer:

A is denser than B as it's volume for the same mass is smaller.

Explanation:

Hello.

In this case, we first need to take into account that the density of each metal A and B is computed by dividing the mass over the volume of each metal which is actually computed by substracting the volume of water from the volume of the water and the solid:

V_A=50.0mL-38.0mL=12.0mL\\\\V_B=60.0mL-38.0mL=22.0mL

Next, we compute the densities as shown below:

\rho_A=\frac{m_A}{V_A}=\frac{5.00g}{12.0mL}=0.42g/mL\\  \\\rho_B=\frac{m_B}{V_B}=\frac{5.00g}{22.0mL}=0.23g/mL

In such a way, A is denser is B as it's volume for the same mass is smaller.

Best regards.

4 0
3 years ago
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