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NikAS [45]
3 years ago
13

How many sulfur atoms are present in 25.6 g of Al2(S2O3)3

Chemistry
1 answer:
IgorC [24]3 years ago
5 0

Given the mass of Al_{2}(S_{2}O_{3})_{3}=25.6 g

The molar mass of Al_{2}(S_{2}O_{3})_{3}=390.35g/mol

Converting mass of Al_{2}(S_{2}O_{3})_{3}to moles:

25.6 g Al_{2}(S_{2}O_{3})_{3}*\frac{1molAl_{2}(S_{2}O_{3}}{390.35 gAl_{2}(S_{2}O_{3}} =0.0656molAl_{2}(S_{2}O_{3}

Converting mol Al_{2}(S_{2}O_{3})_{3}to mol S:

0.0656mol Al_{2}(S_{2}O_{3})_{3}*\frac{6molS}{1mol Al_{2}(S_{2}O_{3})_{3}}=0.3936 molS

Converting mol S to atoms of S using Avogadro's number:

1 mol = 6.022*10^{23}atoms

0.3936mol S *\frac{6.022*10^{23}atoms S}{1 mol S}=2.37*10^{23} S atoms

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What is a single layer of graphite called<br> Asking for GCSE Chemistry
lara31 [8.8K]

Answer:

GRAPHENE is a single layer of graphite

Explanation:

each carbon atom bonded to 3 other carbon atoms forming a hexagonal lattice

8 0
2 years ago
Consider the following balanced equation for the following reaction:
castortr0y [4]

Answer:

47.47 g of CO₂ is the amount formed.

Explanation:

The reaction is:

2C₆H₅COOH(aq) + 15O₂(g) → 14CO₂(g) + 6H₂O(l)

Let's apply the formula for the percent yield

Percent yield of reaction = (Produced yield/Theoretical yield) . 100

First of all we convert the moles of CO₂ to mass: 1.30 mol . 44 g /1 mol = 57.2 g. So now, we replace:

(Produced yield / 57.2 g ). 100 = 83

Produced yield / 57.2 g  = 83 / 100

Produced yield / 57.2 g  = 0.83

Produced yield = 0.83 . 57.2g → 47.47 g of CO₂

8 0
3 years ago
Read 2 more answers
A car moving at 12 m/s applies its brakes and comes to a stop in 2 s. What was its acceleration?​
vredina [299]

Answer:

<h2>6 m/s²</h2>

Explanation:

The acceleration of an object given it's velocity and time taken can be found by using the formula

a =  \frac{v}{t}  \\

where

a is the acceleration

v is the velocity

t is the time

From the question we have

a =  \frac{12}{2}  \\

We have the final answer as

<h3>6 m/s²</h3>

Hope this helps you

8 0
3 years ago
What is the mass of 7 moles of Nitrogen?
Igoryamba

Hey there!

Molar mass of nitrogen is 14.007 g.

We have 7 moles.

Multiply 7 by 14.007.

7 x 14.007 = 98.049

7 moles of nitrogen has a mass of 98.049 grams.

Hope this helps!

8 0
3 years ago
Which of the following best describe the particles present in a 2.0 M aqueous solution of Al(NO3)3?2 M Al3+(aq) and 18 M NO3-(aq
zvonat [6]

Answer:

The correct answer is: 2M Al3+(aq) and 6 M NO3-(aq)

Explanation:

Step 1: Data given

2.0 M Al(NO3)3

Step 2:

Al(NO3)3 in water will dissociate as following:

Al(NO3)3 → Al^3+ + 3NO3^-

For 1 mol of Al(NO3)3 we will have 1 mol of Al^3+ and 3 moles of NO3^-

We know that the molarity of Al(NO3)3 = 2.0 M, this means 2.0 mol/ L

The mol ratio Al(NO3)3 and Al^3+ is 1:1 so the molarity of Al^3+ is<u> 2.0 M</u>

The mol ratio Al(NO3)3 and NO3^- is 1:3 so the molarity of NO3^- is<u> 6.0M</u>

The correct answer is: 2M Al3+(aq) and 6 M NO3-(aq)

3 0
3 years ago
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