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NikAS [45]
3 years ago
13

How many sulfur atoms are present in 25.6 g of Al2(S2O3)3

Chemistry
1 answer:
IgorC [24]3 years ago
5 0

Given the mass of Al_{2}(S_{2}O_{3})_{3}=25.6 g

The molar mass of Al_{2}(S_{2}O_{3})_{3}=390.35g/mol

Converting mass of Al_{2}(S_{2}O_{3})_{3}to moles:

25.6 g Al_{2}(S_{2}O_{3})_{3}*\frac{1molAl_{2}(S_{2}O_{3}}{390.35 gAl_{2}(S_{2}O_{3}} =0.0656molAl_{2}(S_{2}O_{3}

Converting mol Al_{2}(S_{2}O_{3})_{3}to mol S:

0.0656mol Al_{2}(S_{2}O_{3})_{3}*\frac{6molS}{1mol Al_{2}(S_{2}O_{3})_{3}}=0.3936 molS

Converting mol S to atoms of S using Avogadro's number:

1 mol = 6.022*10^{23}atoms

0.3936mol S *\frac{6.022*10^{23}atoms S}{1 mol S}=2.37*10^{23} S atoms

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6 0
3 years ago
An aqueous solution is prepared by dissolving 15.6 g of Cu(NO3)2 ⋅ 6 H2O in water and diluting to 345 mL of solution. What is th
Vladimir [108]

<u>Answer:</u> The molarity of NO_3^- ions in the solution is 0.306 M

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Mass of solute (Cu(NO_3)_2.6H_2O) = 15.6 g

Molar mass of (Cu(NO_3)_2.6H_2O) = 295.6 g/mol

Volume of solution = 345 mL

Putting values in above equation, we get:

\text{Molarity of }Cu(NO_3)_2.6H_2O=\frac{15.6g\times 1000}{295.6g/mol\times 345mL}\\\\\text{Molarity of }Cu(NO_3)_.6H_2O=0.153M

As, 1 mole of (Cu(NO_3)_2.6H_2O) produces 1 mole of copper (II) ions and 2 moles of nitrate ions.

So, molarity of NO_3^- ions = (2 × 0.153) = 0.306 M

Hence, the molarity of NO_3^- ions in the solution is 0.306 M

3 0
3 years ago
Balance the word equation then determine the sum of all coefficients.
Minchanka [31]

The sum of all coefficients = 7

<h3>Further explanation</h3>

Given

The word equation

Required

The sum of all coefficients

Solution

The chemical equation can be expressed in terms of:

  • word equation
  • skeleton equation
  • balanced equation

Convert the word equation into a chemical equation(skeleton) :

Ga + Cl₂ → GaCl₃

Balanced equation

2Ga + 3Cl₂ → 2GaCl₃

The sum of all coefficients :

= 2+3+2

= 7

7 0
3 years ago
How many grams are in 1.2 x 1024 atoms of sodium?
jarptica [38.1K]

Answer:

46 g

Explanation:

First we <u>convert 1.2 x 10²⁴ atoms of sodium into moles</u>, using <em>Avogadro's number</em>:

  • 1.2x10²⁴ atoms ÷ 6.023x10²³ atoms/mol = 2.0 mol

Then we <u>convert 2.0 moles of sodium into grams</u>, using <em>sodium's molar mass</em>:

  • 2.0 mol Na * 23 g/mol = 46 g

Thus, there are 46 grams in 1.2x10²⁴ atoms of sodium.

3 0
3 years ago
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