Question

Please help!

Answer 1

Answer:

y = 3x - 5  

Step-by-step explanation:

1) First, place the given equation in slope-intercept form, represented by the formula $y = mx +b$, to find the slope. Whatever $m$ or the coefficient of x-term is will be the slope. Isolate y in the equation:

$x + 3y = -6\\3y = -x -6\\y = -\frac{1}{3}x-2$

So, the slope of that line is $-\frac{1}{3}$. Lines that are perpendicular have slopes that are opposite reciprocals, thus the slope of the new line will be 3.

2) Now, use the point-slope formula $y-y_1 = m (x-x_1)$ to find the equation of the new line. Substitute real values for the $m$, $x_1$ and $y_1$ in the equation.

Since $m$ represents the slope, substitute $-\frac{1}{3}$ in its place. Since $x_1$ and $y_1$ represents the x and y values of one point the line passes through, substitute the x and y values of (-1,-8) into the formula as well. Then, isolate the y in the resulting equation to put the equation in slope-intercept form and find an answer:

$y-(-8) = 3 (x-(-1))\\y + 8 = 3(x+1)\\y + 8=3x + 3\\y = 3x -5$