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The lengths of HJ and JK are 50 and 72 respectively.
Given: J is between H and K. the length of HJ=2x+4, JK=3x+3, and HK=22.
The line HJ and JK are collinear then the total length is given as: HJ+JK=HK
substitute values
⇒ (2x+4)+(3x+3)=22
⇒ 5x+7=22
⇒ 5x=22-7
⇒ 5x=15
⇒ x=3
Thus, the length of HJ is (2x+4)=(2*3+4)=10
And the length of JK is (3x+3)=(3*3+3)=12
Learn more about collinear lines here: brainly.com/question/27943430
#SPJ10
Answer:
1.335 Kilograms
Step-by-step explanation:
Answer:
Option A.
Step-by-step explanation:
If graph of a polynomial intersects the x-axis at x=c, where c is a constant, then (x-c) is a factor of that polynomial.
We need to find the factor of the polynomial function f(x) graphed on the coordinate plane.
From the given graph it is clear that graph of f(x) intersects the x-axis at x=3. It means (x-3) is a factor of f(x).
Therefore, the correct option is A.
Answer:
z=25
Step-by-step explanation:
7x+2y=z
7(3)+2(2)=z
21+4=z
25=z
Hope this helps! :)
