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Ratling [72]
2 years ago
15

Problem

Mathematics
2 answers:
Sergeu [11.5K]2 years ago
8 0

The lengths of HJ and JK are 50 and 72 respectively.

Given: J is between H and K. the length of HJ=2x+4, JK=3x+3, and HK=22.

The line HJ and JK are  collinear then the total length is given as: HJ+JK=HK

substitute values

⇒ (2x+4)+(3x+3)=22

⇒ 5x+7=22

⇒ 5x=22-7

⇒ 5x=15

⇒ x=3

Thus, the length of HJ is (2x+4)=(2*3+4)=10

And the length of JK is (3x+3)=(3*3+3)=12

Learn more about collinear lines here: brainly.com/question/27943430

#SPJ10

kykrilka [37]2 years ago
6 0

Answer:

The lengths of HJ and JK are 50 and 72 respectively.

Given:

J is between H and K.

HJ=2x+4

JK=3x+3

HK=22

Step-by-step explanation:

The total length is given as:

HJ+JK=HK

⇒ (2x+4)+(3x+3)=22

⇒ 5x+7=22

⇒ 5x=22-7

⇒ 5x=15

⇒ x=3

Thus, the length of HJ is (2x+4)=(2*3+4)=10

And the length of JK is (3x+3)=(3*3+3)=12

See more detailed solution at

brainly.com/question/27943430

#SPJ10

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72 miles per gallons

Step-by-step explanation:

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3 years ago
(11-8)x3+7+27-3<br> (18÷3)+6+(14-8)x5<br> (11-7)x6+4+32-4
horsena [70]

The results of the arithmetic evaluations as given in the task content are; 40,42 and 62.

<h3>What are the results of the arithmetic evaluations?</h3>

The arithmetic operations above can be evaluated and simplified as follows;

(11-8)x3+7+27-3 = (3×3)+7+27-3 = 40.

(18÷3)+6+(14-8)x5 = (6)+6+(6)x5 = 42.

(11-7)x6+4+32-4 = (5×6) +4 +32-4 = 62.

Read more on arithmetic evaluations;

brainly.com/question/4694189

#SPJ1

8 0
2 years ago
If BAC = ADB = 90. The value of x is
alexandr1967 [171]
I’m extremely sorry, I am stumped
8 0
3 years ago
Tengo 5 cubos de colores. Uno rojo, uno amarillo, uno verde, uno azul claro y uno azul oscuro. ¿De cuántas formas puedo organiza
rusak2 [61]

Answer:

72 formas

Step-by-step explanation:

Primero vamos a calcular de cuántas formas se puede organizar los 5 cubos en una columna utilizando la regla de la multiplicación:

5 * 4 * 3 * 2 * 1 = 120

Porque tenemos 5 cubos para poner en la base de la columna, luego 4 cubos para la segunda posición de la columna, luego 3 cubos y así hasta organizar todos los cubos.

Luego vamos a calcular de cuántas formas podemos organizar los 5 cubos de tal forma que los cubos azules se toquen entre sí. Para esto vamos a contar los dos cubos azules como si fueran uno solo, es decir, sólo tendríamos "4 cubos" y podríamos organizar los cubos de 24 formas distintas:

4 * 3 * 2 * 1 = 24

Por otro lado, los 2 cubos azules pueden ser organizados de dos formas diferentes: primero el claro y luego el oscuro o primero el oscuro y luego el claro.

Es decir que hay 24 formas distintas de organizar los cubos en donde primero va el claro y luego el oscuro y hay 24 formas de organizar los cubos en donde primero va el oscuro y luego el claro.

Esto significa que de las 120 formas de organizar los 5 cubos, 48 formas tienen los cubos azules juntos y en 72 (120-48) formas los dos cubos azules no se tocan entre sí.

7 0
3 years ago
Refer to the diagram shown.
lions [1.4K]

Answer:

x=5

Step-by-step explanation:

According to SSS, RPS and RPQ should be similar angles. Since the length RP is the same, then RQP and RSP should be similar too. Therefore PRS and PRQ should be similar too. Since QP and RS are the same (7) then QR and PS needs to be same in length too.

2x+3 = 4x-7

10 = 2x

x=5

5 0
3 years ago
Read 2 more answers
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