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Ratling [72]
2 years ago
15

Problem

Mathematics
2 answers:
Sergeu [11.5K]2 years ago
8 0

The lengths of HJ and JK are 50 and 72 respectively.

Given: J is between H and K. the length of HJ=2x+4, JK=3x+3, and HK=22.

The line HJ and JK are  collinear then the total length is given as: HJ+JK=HK

substitute values

⇒ (2x+4)+(3x+3)=22

⇒ 5x+7=22

⇒ 5x=22-7

⇒ 5x=15

⇒ x=3

Thus, the length of HJ is (2x+4)=(2*3+4)=10

And the length of JK is (3x+3)=(3*3+3)=12

Learn more about collinear lines here: brainly.com/question/27943430

#SPJ10

kykrilka [37]2 years ago
6 0

Answer:

The lengths of HJ and JK are 50 and 72 respectively.

Given:

J is between H and K.

HJ=2x+4

JK=3x+3

HK=22

Step-by-step explanation:

The total length is given as:

HJ+JK=HK

⇒ (2x+4)+(3x+3)=22

⇒ 5x+7=22

⇒ 5x=22-7

⇒ 5x=15

⇒ x=3

Thus, the length of HJ is (2x+4)=(2*3+4)=10

And the length of JK is (3x+3)=(3*3+3)=12

See more detailed solution at

brainly.com/question/27943430

#SPJ10

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Let's check all functions.
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    Evaluated with -3 means that x = -3.
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3. f(x)=x²<span>+2x when evaluated with -3 gives you the value of 3
</span>    Evaluated with -3 means that x = -3.
    f(-3) = (-3)² + 2 * (-3) = 9 - 6 = 3
    3 = 3, so this is correct.

4. f(x)=x²-3x when evaluated with -3 gives you the value of 3
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Answer:

Expected revenue from the single trip is $ 13.14

Step-by-step explanation:

                              y

p(x,y)                   0               1                                 2                g(x)

x    0           0.025              0.015                       0.010            0.05

1                  0.050            0.030                        0.020           0.1  

2                   0.115             0.075                        0.050           0.24

3                  0.150              0.090                      0.060             0.3

<u>4                   0.100             0.060                     0.040              0.2 </u>

h(y)              0.325              0.27                       0.18  

E (x+Y) = E(X) +E(Y)

E(X)= ∑ xi g(x)i

       = ( 0*0.05) + (1*0.1) + (2* 0.24) + (3*0.3) + (4*0.2)

        = 0 + 0.1+ 0.48 + 0.9+0.8

        =2.28

E(Y)= ∑yi h(y)

      = (0* 0.325) + (1*0.27) + (2*0.18)    

       = 0 +0.27+ 0.36

        = 0.63

E (x+Y) = E(X) +E(Y)

             = 2.28 + 0.63

                = 2.91

But the equation is 3x+ 10y

E(3x+ 10y)= 3E(x) + 10 E(y)

                   = 3(2.28) + 10 (0.63)

                       = 6.84 +6.3

                         = 13.14

Expected revenue from the single trip is $ 13.14

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