Sum of all sides of triangle =perimeter of it
x+4+x+2x-y=24
4x-y=20
y=4x-20
H^2=p^2+b^2
(x+4)^2=x^2+(-2x+20)^2
From here you can calculate value of x and y
x^2+16+8x=5x^2-80x+400
4x^2-88x+384
=x^2-22x+96
you use quadratic formula to calculate x and y
Remember greatest value should be x and smallest should be y as the conditions given above
100,203=>One hundred thousand, two hundred and three...
hope it helps !!!
<span>5x / 25x^4 = 5/x^3
</span><span>x^3 / 5x^14 = 1/5x^11</span>t is nonequivalent
hope this helps
Are you sure you said the whole problem cuz that is impossible to answer
Answer:
There will be 20 914 rupees in the amount at the end of 3 years.
Step-by-step explanation:
The amount of rupes after t years in compound interest is given by:
![A(t) = A(0)(1+r)^{t}](https://tex.z-dn.net/?f=A%28t%29%20%3D%20A%280%29%281%2Br%29%5E%7Bt%7D)
In which A(0) is the initial amount and r is the interest rate, as a decimal.
Hiran invests 20 000 rupees in an account for 3 years at 1.5% per year compound interest.
This means that
. So
![A(t) = A(0)(1+r)^{t}](https://tex.z-dn.net/?f=A%28t%29%20%3D%20A%280%29%281%2Br%29%5E%7Bt%7D)
![A(t) = 20000(1+0.015)^{t}](https://tex.z-dn.net/?f=A%28t%29%20%3D%2020000%281%2B0.015%29%5E%7Bt%7D)
![A(t) = 20000(1.015)^{t}](https://tex.z-dn.net/?f=A%28t%29%20%3D%2020000%281.015%29%5E%7Bt%7D)
Work out the total amount of money in the account at the end of 3 years.
This is A(3). So
![A(3) = 20000(1.015)^{3} = 20913.6](https://tex.z-dn.net/?f=A%283%29%20%3D%2020000%281.015%29%5E%7B3%7D%20%3D%2020913.6)
Rounding to the nearest rupee.
There will be 20 914 rupees in the amount at the end of 3 years.