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galben [10]
3 years ago
10

Pls help ASAP! Thank you! (10) points.

Mathematics
1 answer:
qaws [65]3 years ago
6 0

Answer:

Quadratic polynomial function

Step-by-step explanation:

Hope This Hels!

Plz Mark Brainliest!

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x\geq 6

y\geq 5

Step-by-step explanation:

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How many edges does a decagonal pyramid have
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In geometry, the decagonal prism is the eighth in the infinite set of prisms, formed by ten square side faces and two regular decagon caps. With twelve faces, it is one of many nonregular dodecahedra. The decagonal prism has 12 faces, 30 edges, and 20 vertices.
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13) A hexagon has 6 equal sides! Ms. Sears asked the students to find the perimeter if all sides are equal to 2x + y. One studen
mestny [16]

Answer:

None of the answers are right

Step-by-step explanation:

Since a hexagon has 6 sides, and perimeter is the length of all the sides summed up, we can multiply 6 by 2x+y to find the perimeter.

6(2x+y)

Distribute the 6 to each term in the parentheses:

6(2x)+6(y)

12x+6y is the perimeter. None of the answers are right.

7 0
2 years ago
twice a number plus three times another number equals 4. three times the first number plus four times the other number is 7. wha
Drupady [299]

Answer:

x=5, y=-2. (5, -2).

Step-by-step explanation:

2x+3y=4

3x+4y=7

----------------

3(2x+3y)=3(4)

-2(3x+4y)=-2(7)

----------------------

6x+9y=12

-6x-8y=-14

-----------------

y=-2

2x+3(-2)=4

2x-6=4

2x=4+6

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5 0
3 years ago
Giá trị x thoả mãn x(x − 3) + x − 3 =0 là
svet-max [94.6K]

Here we will use the trial and error method.

  • We will try putting different values of x.
<h3 /><h3>1st of all</h3><h3>x=1</h3>

\begin{gathered}\\ \sf\longmapsto 1(1-3)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto (-2)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2-2=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -4≠0\end{gathered}

<h2>Now,</h2><h3>x=2</h3>

\begin{gathered}\\ \sf\longmapsto 2(2-3)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 2(-1)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -3≠0\end{gathered}

<h2>Again,</h2><h3>x=3</h3>

\begin{gathered}\\ \sf\longmapsto 3(3-3)+3-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3(3-3)=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3×0=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 0=0\end{gathered}

<h3>☣Hence, The value of X as 3 satisfies the equation!</h3>
5 0
3 years ago
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