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kirill [66]
3 years ago
11

Please help i’ll give brainliest if you help thanks

Mathematics
1 answer:
navik [9.2K]3 years ago
6 0

Answer:

5

Step-by-step explanation:

as the 2nd term is b, and the coeffiecnt is the number next to the term

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The total attendance for Sunday's service was 266. If there were 18 more people at the morning service than people at the evenin
maria [59]
There were 151 at the morning service and 115 at the evening service<span />
4 0
4 years ago
Write the quadratic equation 3x ^ 2 - 9x = 5 standard form ax²+bx+c=0? in the
sleet_krkn [62]
The answer to your question is B 3x^2-9x-5=0.
8 0
3 years ago
If a watch has a 0.12 defect rate. what is the probability that the watch has fewer than 3 defects in a run of 75 chimes?
Maslowich

Answer:

(\frac{88}{100})^{75} + \binom{75}{1} (\frac{88}{100})^{74}(\frac{12}{100}) + \binom{75}{2} (\frac{88}{100})^{73}(\frac{12}{100})^{2}

Step-by-step explanation:

If a watch has fewer than three defects, then either 1.) It has no defects, 2.) it has exactly 1 defect, or 3.) it has exactly 2 defects.

1.) The probability that the watch has no defects is (\frac{88}{100})^{75}, because for every chime there is a probability of \frac{88}{100} that there is no defect

2.) The probability that the watch has exactly 1 defect is (\frac{88}{100})^{74}(\frac{12}{100}) times the number of ways you can choose 1 of 75 of the chimes to be defective, which is \binom{75}{1}, so the probability that the watch has exactly 1 defect is \binom{75}{1} (\frac{88}{100})^{74}(\frac{12}{100}).

3.) For the same reason as 2.), the probability that the watch has exactly two defects is \binom{75}{2} (\frac{88}{100})^{73}(\frac{12}{100})^{2}

Since 1.), 2.), and 3.) are mutually exclusive events, the probability of their union is simply the probability of each of them added together, which is (\frac{88}{100})^{75} + \binom{75}{1} (\frac{88}{100})^{74}(\frac{12}{100}) + \binom{75}{2} (\frac{88}{100})^{73}(\frac{12}{100})^{2}

8 0
3 years ago
candy box is made from a piece of cardboard that measures 45 by 24 inches. Squares of equal size will be cut out of each comer.
den301095 [7]

Answer:

Each square should have 5 inches of side and area = 25 square inches.

Step-by-step explanation:

Candy box is made that measures 45 by 24 inches.

Let the squares of equal size x inches has been cut out of each corner.

The sides will then be folded up to form a rectangular box.

Now we have to find the size of square that should be cut from each corner to obtain maximum volume of the box.

Now the box is with length = (45 - 2x) inches

and width = (24 - 2x) inches

and height = x inches

Volume of the candy box = Length × width × height

V = (45 - 2x)(24 - 2x)(x)

V = x(1080 - 48x -90x + 4x²)

  = x(1080 - 138x + 4x²)

  = 4x³ - 138x² + 1080x

Now we will find the derivative of volume and equate it to zero.

\frac{dV}{dx}=12x^{2}-276x+1080=0

12(x² - 23x + 90) = 0

x² - 23x + 90 = 0

x² - 18x - 5x + 90 = 0

x(x - 18) - 5(x - 18) = 0

(x - 5)(x - 18)=0

x = 5, 18

Now for x = 18 Width of the box will be = (24 - 2×18) = 24 - 36 = -12

Which is not possible.

Therefore, x = 5 will be the possible value.

Therefore, square having area 25 square inches should be cut out from each corner to get the maximum volume of candy box.

6 0
4 years ago
Above is the question
sweet [91]

Answer:

its A

Step-by-step explanation:

asymptotes:=-1 and hole:x=4

6 0
3 years ago
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