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Firdavs [7]
3 years ago
5

A 35-foot tall pole is leading towards a building. To stop the pole from leaning

Mathematics
1 answer:
Lapatulllka [165]3 years ago
5 0

9514 1404 393

Answer:

  38.5°

Step-by-step explanation:

You are given all three side lengths of the relevant triangle, so the Law of Cosines can be used to find any desired angle. If we call the desired angle C, then that law tells you ...

  C = arccos((a² +b² -c²)/(2ab))

where a and b are the triangle side lengths adjacent to the angle of interest, and c is the side opposite. Here, 'a' and 'b' are the pole and cable lengths, and 'c' is the distance of the stake from the pole.

  C = arccos((35² +48² -30²)/(2·35·48)) = arccos(2629/3360)

  C ≈ 38.515°

The cable makes an angle of about 38.5° with the pole.

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Answer:

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Step-by-step explanation:

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then

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Explain how you determined the length of segment LM using 2-3 sentences or explain your steps used to find the value for y.
anastassius [24]
<h2>Explanation:</h2><h2 />

The question is incomplete so I'll assume the segment LM is defined by these two points:

L(4,3) \\ \\ M(5,8)

So we can find the length of the segment by using the distance formula:

d=\sqrt{(x_{1}-x_{2})^2+(y_{1}-y_{2})^2} \\ \\ \\ So, \ if \ we \ call: \\ \\ L(x_{1},y_{1}) \ and \ M(x_{2},y_{2}) \\ \\ \\ Then: \\ \\ \overline{LM}=\sqrt{(4-5)^2+(3-8)^2} \\ \\ \overline{LM}=\sqrt{(-1)^2+(-5)^2} \\ \\ \overline{LM}=\sqrt{1+25} \\ \\ \boxed{\overline{LM}=\sqrt{26}}

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3 years ago
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