What is the probability of all cogs being defective

Mathematics

1 answer:

Sonbull [250]3 years ago

5 0

Prob (first defective) = 4 / 20 = 1/5

Prob(2nd defective) = 3/19

Prob (3rd defective) = 2/18 = 1/9

Pron 4th defective) = 1/ 17

Prob ( all 4 defective) = 1/5 * 3/19 * 1/9 * 1/17 = 1 / 4845 answer

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vlada-n [284]

$\bf h=20ln(3t+2)+30\\\\
-------------------------------\\\\
\boxed{a}\\\\
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\\\\\\
h\approx 43.86
\\\\\\
\boxed{b}\\\\
\stackrel{1~meter}{h=100}\qquad 100=20ln(3t+2)+30\implies 70=20ln(3t+2)
\\\\\\
\cfrac{70}{20}=ln(3t+2)\implies \stackrel{\textit{log cancellation rule}}{e^{\frac{7}{2}}=e^{ln(3t+2)}}\implies e^{\frac{7}{2}}=3t+2
\\\\\\
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$\bf \boxed{c}\\\\
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Likurg_2 [28]

Answer:

the 1st one

Step-by-step explanation:

I passes it in the quiz

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