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2 years ago

HELP 100 POINTS ANSWER IT PLEASE

Mathematics

2 answers:

LUCKY_DIMON [66]2 years ago

5 0

Answer:

Step-by-step explanation:

Using a graphing calculator, plot (x,y) points

x = no. of jobs

y = no. of workers needed

and plot the functions from the options to know which function fits the data

Bingel [31]2 years ago

4 0

Answer:

$\boxed{\text{\large $ y=96.1\sqrt{x} $}}$

Step-by-step explanation:

Using a graphing calculator, plot (x,y) points

x = no. of jobs
y = no. of workers needed

and plot the functions from the options to know which function fits the data

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When theres two negative nubers?are u suppose to add

Nina [5.8K]

Answer:

Step-by-step explanation:

6 0

3 years ago

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Suppose that the length of a side of a cube X is uniformly distributed in the interval 9

Nastasia [14]

Answer:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

Step-by-step explanation:

Given

$9 < x < 10$ --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

$v = x^3$

For a uniform distribution, we have:

$x \to U(a,b)$

and

$f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.$

$9 < x < 10$ implies that:

$(a,b) = (9,10)$

So, we have:

$f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Solve

$f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Recall that:

$v = x^3$

Make x the subject

$x = v^\frac{1}{3}$

So, the cumulative density is:

$F(x) = P(x < v^\frac{1}{3})$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$ becomes

$f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.$

The CDF is:

$F(x) = \int\limits^{v^\frac{1}{3}}_9 1\ dx$

Integrate

$F(x) = [v]\limits^{v^\frac{1}{3}}_9$

Expand

$F(x) = v^\frac{1}{3} - 9$

The density function of the volume F(v) is:

$F(v) = F'(x)$

Differentiate F(x) to give:

$F(x) = v^\frac{1}{3} - 9$

$F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}$

$F'(x) = \frac{1}{3}v^{-\frac{2}{3}}$

$F(v) = \frac{1}{3}v^{-\frac{2}{3}}$

So:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

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2 years ago

Jodi has two bank accounts. Her parents started Account A for her. It currently has $100 in it, and Jodi deposits $20 into it ea

Law Incorporation [45]

Answer:

(f+g)(x) = 60x + 400

Step-by-step explanation:

Given :

Amount in account A:

f(x) = 20x + 100

Amount in account B :

g(x) = 40x + 300

Total amount in Account A and B:

f(x) + g(x) = (20x + 100) + (40x + 300)

(f+g)(x) = (20x + 40x) + (100 + 300)

(f+g)(x) = 60x + 400

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2 years ago

Write 3 tens 9 ones in another way

Vsevolod [243]

3 tens is 3 * 10 = 30
9 ones is 9 * 1 = 9
30 + 9 = 39
Answer: 39

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3 years ago

a restaurant sells a coffee refill mug for $6.75. Each refill costs $1.25. Last month keith spent $31.75 on a mug and refills wr

evablogger [386]

y= 1.25x+6.75
Make 31.75 y because that is the total cost he paid.
1.25x+6.75=31.75
1.25x=25
x=20
So he had 20 refills.

7 0

3 years ago

Read 2 more answers