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Illusion [34]
3 years ago
13

Which is the graph of x^2/16 + y^2/ 9 =1

Mathematics
1 answer:
jeka943 years ago
6 0

Answer:

B

Step-by-step explanation:

you can figure this out by replace the x and y with any one of the x, y positions and if the answer is 1 it's correct.

I tried 0^2/16+3^2/9 and I got 1.

I tried this with the first two but they didn't work.

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Please help for online school
Stels [109]

Answer:

4

Step-by-step explanation:

The diagram shows that the one triangle can be divided into two equal right triangles.  Because of this, you can use the Pythagorean Theorem to solve this problem.  a and b are the two sides of the angles, and c is the hypotenuse.

The given lengths are 5 as the hypotenuse and 3 as one length.  (You have 3 as a given length because the two triangles have a length of 6  on one side.  6/2 = 3)

a² + b² = c²

a² = c² - b²

a² = 5² - 3²

a² = 25² - 9²

a² = 16

a = 4

4 0
3 years ago
To prove that ΔDEF ≅ ΔDGF by SSS, what additional information is needed?
FinnZ [79.3K]

Answer:

DE ≅ DG

Step-by-step explanation:

3 0
3 years ago
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three points are plotted in the coordinate plane which table of X and Y values corresponds to these points​
weeeeeb [17]

Answer:

Where is the table?

Step-by-step explanation:

4 0
2 years ago
Because of safety considerations, in May 2003 the Federal Aviation Administration (FAA) changed its guidelines for how small com
Rasek [7]

Answer:

a) The 95% confidence interval for the mean summer weight (including carry-on luggage) of Frontier Airlines passengers is between 179 and 187 pounds. This means that we are 95% sure that the mean summer weight of all Frontier Airlines passengers is between these two values.

b)

The 95% confidence interval for the mean winter weight (including carry-on luggage) of Frontier Airlines passengers is between 185.4 pounds and 194.6 pounds. This means that we are 95% sure that the mean winter weight of all Frontier Airlines passengers is between these two values.

c) They are respected, as the upper bound of both intervals is below the new FAA recommendations.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve these questions.

Question a:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 100 - 1 = 99

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 99 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 1.9842

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.9842\frac{20}{\sqrt{100}} = 4

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 183 - 4 = 179 pounds.

The upper end of the interval is the sample mean added to M. So it is 183 + 4 = 187 pounds.

The 95% confidence interval for the mean summer weight (including carry-on luggage) of Frontier Airlines passengers is between 179 and 187 pounds. This means that we are 95% sure that the mean summer weight of all Frontier Airlines passengers is between these two values.

Question b:

Critical value is the same(same sample size and confidence level).

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.9842\frac{23}{\sqrt{100}} = 4.6

The lower end of the interval is the sample mean subtracted by M. So it is 190 - 4.6 = 185.4 pounds.

The upper end of the interval is the sample mean added to M. So it is 190 + 4.6 = 194.6 pounds.

The 95% confidence interval for the mean winter weight (including carry-on luggage) of Frontier Airlines passengers is between 185.4 pounds and 194.6 pounds. This means that we are 95% sure that the mean winter weight of all Frontier Airlines passengers is between these two values.

c. The new FAA recommendations are 190 pounds for summer and 195 pounds for winter. Comment on these recommendations in light of the confidence interval estimates from Parts (a) and (b).

They are respected, as the upper bound of both intervals is below the new FAA recommendations.

7 0
3 years ago
It would take 5 taps 150 mins to fill a pool.
Maksim231197 [3]

Answer:

250 mins

Step-by-step explanation:

since number of taps times time is constant

4 0
3 years ago
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