Answer:
Yes, the average speed for the entire trip from A to C is equal to ![80\frac{km}{h}](https://tex.z-dn.net/?f=80%5Cfrac%7Bkm%7D%7Bh%7D)
Step-by-step explanation:
The average speed of an object is defined as the distance traveled divided by the time elapsed. Velocity is a vector quantity, and average velocity can be defined as the displacement divided by the time. For the special case of straight line motion in the x direction, the average velocity takes the form:
![V_a_v_e_r_a_g_e=\frac{x_2-x_1}{t_2-t_1}=\frac{Δx}{Δt}](https://tex.z-dn.net/?f=V_a_v_e_r_a_g_e%3D%5Cfrac%7Bx_2-x_1%7D%7Bt_2-t_1%7D%3D%5Cfrac%7B%CE%94x%7D%7B%CE%94t%7D)
If the beginning and ending velocities for the motion are known, and the acceleration is constant, the average velocity can also be expressed as:
![V_a_v_e_r_a_g_e=\frac{V_1+V_2}{2}](https://tex.z-dn.net/?f=V_a_v_e_r_a_g_e%3D%5Cfrac%7BV_1%2BV_2%7D%7B2%7D)
We Know that:
![V_1=70\frac{km}{h} \\\\V_2=90\frac{km}{h}](https://tex.z-dn.net/?f=V_1%3D70%5Cfrac%7Bkm%7D%7Bh%7D%20%5C%5C%5C%5CV_2%3D90%5Cfrac%7Bkm%7D%7Bh%7D)
Replacing the values:
![V_a_v_e_r_a_g_e=\frac{70+90}{2} =\frac{160}{2}=80\frac{km}{h}](https://tex.z-dn.net/?f=V_a_v_e_r_a_g_e%3D%5Cfrac%7B70%2B90%7D%7B2%7D%20%3D%5Cfrac%7B160%7D%7B2%7D%3D80%5Cfrac%7Bkm%7D%7Bh%7D)
Answer:
Step-by-step explanation:
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I think it's D because you times everything from the left column to the right column
Since x and y are directly related, the equation for their comparison will look like
kx = y
where k is your constant. They give you an instance in the problem where x = 27 and y = 81. Plug this into the above equation and solve for k.
kx = y
k (27) = 81
k = 3
Thus, the constant of variation is 3.