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Jobisdone [24]
3 years ago
12

5. Hotel A and Hotel B had a total of 6500 guests. After of the guests in Hotel A and of the guests

Mathematics
1 answer:
Jobisdone [24]3 years ago
4 0
I believe the correct answer is 6,240 so you had subtract 260 from 6500
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A stack of cards is numbered 1 to 21. Kelly pulls one card from the stack. What is the best approximation for the probability th
ASHA 777 [7]
The correct answer is 48%

There are 10 even numbers from 1 to 21.

That makes the probability of an even number 10 out 21.

10 / 21 x 100 = 48%
8 0
3 years ago
Mr. Singh had three sheets of stickers. He gave 20 stickers from each sheet to his students and has 12 total stickers left. Writ
djverab [1.8K]

Step-by-step explanation:

3x-3(20)=12

3x=72

x=24.

24 stickers on each sheet

4 0
3 years ago
Evaluate the following when $a = 3$, $b = \frac14$, and $c = 5$: \[ \frac{b^{-1}}{ca^{-1} - ac^{-1}}. \] Thank you so much!
pickupchik [31]

\dfrac{b^{-1}}{ca^{-1}-ac^{-1}}=\dfrac{\frac1b}{\frac ca-\frac ac}

Multiply the numerator and denominator by ac:

\dfrac{\frac1b}{\frac ca-\frac ac}\cdot\dfrac{ac}{ac}=\dfrac{\frac{ac}b}{c-a}

Since b=\frac14, we have b^{-1}=\frac1b=4. So substituting the values of <em>a</em>, <em>b</em>, and <em>c</em> gives us

\dfrac{\frac{ac}b}{c-a}=\dfrac{3\cdot5\cdot4}{5-3}=\dfrac{60}2=\boxed{30}

4 0
3 years ago
Read 2 more answers
Please help me with this answer
aivan3 [116]
It should be 56.
each time they are adding an odd number
55+1 = 56
56+3= 59
59+5= 64
64+7= 71
71+9= 80
80+11=91
So; the answer is: 56
6 0
3 years ago
Read 2 more answers
If $a = 4$, $b = 2$, and $c = -5$, then what is the value of $\sqrt[3]{4a^4b^5} + \dfrac{a - c}{(b+c)^2}$?
djverab [1.8K]

Answer:

does not make sensse?

Step-by-step explanation:

8 0
3 years ago
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