If $a = 4$, $b = 2$, and $c = -5$, then what is the value of $\sqrt[3]{4a^4b^5} + \dfrac{a - c}{(b+c)^2}$?
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Answer:
Width 150 meters.
Length = 350 meters.
Step-by-step explanation:
Let us assume the width of the fence = k meters
So, both sides = k + k = 2k meters
Also, the TOTAL fencing length = 600 m
So, the one side length of the fence = (600 - 2 k) meters
AREA = LENGTH x WIDTH
⇒ A(k) = (600 - 2k) (k)
or, A = -2k² + 600 k
The above equation is of the form: ax² +bx + C
Here: a = - 2 , b = 600 and C = 0
As a< 0, the parabola opens DOWNWARDS.
Here, x value is given as:
Solving for the value of k similarly, we get:
Thus the desired width = k = 150 meters
So, the desired dimensions of the plot is width 150 meters.
And length = 650 - 2k = 650 - 300 = 350 meters.