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artcher [175]
2 years ago
10

A car dealership sold 84 cars in April. The dealership wants to increase the number of cars sold by 25% in May. How many cars wi

ll the dealership need to sell to reach their goal?
Mathematics
1 answer:
Agata [3.3K]2 years ago
8 0

Answer:

The car dealer must sell 105 cars in May to reach his goal.

Step-by-step explanation:

Given that the car dealer sold 84 cars in April, and wants to increase his May sales by 25%, to determine the number of cars he must sell to reach his goal it is necessary to perform the following calculation:

84 + (84 x 0.25) = X

84 + 21 = X

105 = X

Therefore, the car dealer must sell 105 cars in May to reach his goal.

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What is the length of the diagonal of the square shown below?
Tatiana [17]

Answer:

sqrt(50)

Step-by-step explanation:

Since it is a right triangle, we can apply the Pythagorem Theorem.

a^2 + b^2 = c^2

25 + 25 = c^2

50 = c^2

c = sqrt(50)

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X + 1/4x = 15. What is the solution to the equation?
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Answer:

Step-by-step explanation:

hello :

X + 1/4x = 15

multiply by 4 : 4x+x = 60

5x=60

now divid by 5 you have : x=12

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What is X:<br> |4x−1|=3 <br><br> |x|=−4
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1

Step-by-step explanation:

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A small plane took 3 hours to fly 960 km from Ottawa to Halifax with a tail wind. On the return trip, flying into the wind, the
Rina8888 [55]

Answer:

  • Wind speed: \rm 40\; km \cdot h^{-1}.
  • Speed of the plane in still air: \rm 320\; km \cdot h^{-1}.

Step-by-step explanation:

This problem involves two unknowns:

  • wind speed, and
  • speed of the plane in still air.

Let the speed of the wind be x \rm \; km \cdot h^{-1}, and the speed of the plane in still air be y\rm \; km \cdot h^{-1}. It takes at least two equations to find the exact solutions to a system of two variables.

Information in this question gives two equations:

  • It takes the plane three hours to travel \rm 960\; km from Ottawa to with a tail wind (that is: at a ground speed of x + y.)
  • It takes the plane four hours to travel \rm 960\; km from Halifax back to Ottawa while flying into the wind (that is: at a ground speed of -x + y.)

Create a two-by-two system out of these two equations:

\left\{ \begin{aligned}&3(x + y) = 960 && (1) \\ &4(-x + y) = 960 && (2) \end{aligned}\right..

There can be many ways to solve this system. The approach below avoids multiplying large numbers as much as possible.

Note that this system is equivalent to

\left\{ \begin{aligned}&4 \times 3 (x + y) = 4\times960 && 4 \times (1) \\ &3\times 4(-x + y) = 3\times 960 && 3 \times (2) \end{aligned}\right..

\left\{ \begin{aligned}&12 x + 12y = 4\times960 && 4 \times (1) \\ &- 12x + 12y = 3\times 960 && 3 \times (2) \end{aligned}\right..

Either adding or subtracting the two equations will eliminate one of the variables. However, subtracting them gives only 1 \times 960 on the right-hand side. In comparison, adding them will give 7 \times 960, which is much more complex to evaluate. Subtracting the second equation (3 \times (2)) from the first (4 \times (1)) will give the equation

(12 - (-12) x = 1 \times 960.

24 x = 960.

x = 40.

Substitute x back into either equation (1) or (2) of the original system. Solve for y to obtain y = 320.

In other words,

  • Wind speed: \rm 40\; km \cdot h^{-1}.
  • Speed of the plane in still air: \rm 320\; km \cdot h^{-1}.
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3 years ago
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Which sentence can represent the inequality 3.5x&gt;7?
Andrei [34K]

Answer:A

Step-by-step explanation:hole this helps

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