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3 years ago

Help giving brainliest...

Mathematics

2 answers:

aksik [14]3 years ago

8 0

Answer:

7, 8, 8,7,8,9

Step-by-step explanation:

brainliest plss!!<3

ICE Princess25 [194]3 years ago

7 0

(5 or more raise the score, 4 or less let it rest) so
1.would round to 7
2.would round to 8
3.would round to 8
4.would round to 7
5.would round to 8
6.would round to 9

Hope this helps

Have a great day/night

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PLEASE HELP FAST

IceJOKER [234]

-4,-9 I took the test and got the same answer.

3 0

3 years ago

Problem 2:

kifflom [539]

Answer:

The answers to the questions about problem 2 are:

The fraction of the length after Priya stops two times is 3/4.
The fraction of the length after Priya stops four times is 15/16.
Priya will never reach the end of the hallway.

Step-by-step explanation:

The explanation about each answer is below:

1. In the first stop, Priya has walked half of the total length, and there would still be half the hallway, however, when she stops the second time, she has walked the half of the half, I mean:

$\frac{1}{2}/2=\frac{1}{4}$

If you add the two values you obtain the total distance traveled by Priya:

$\frac{1}{2}+\frac{1}{4}= \frac{3}{4}$

And the distance traveled in two stops is 3/4 of the total length of the hallway.

2. With four stops the system is the same, we know with two stops Priya travels 3/4 of the hallway, now with the third stop, she will travel half of the remaining distance:

$\frac{1}{4}/2=\frac{1}{8}$

And in the fourth stop she will travel half of the remaining, I mean:

$\frac{1}{8}/2=\frac{1}{16}$

Now, we add all the values of the distances obtained:

$\frac{3}{4}+\frac{1}{8}+\frac{1}{16}= \frac{15}{16}$

So, the distance traveled by Priya in the fourth stop is 15/16 of the total length of the hallway.

3. How we know, the numbers are infinite, in the same forms the distances, by this reason, how the problem says that Priya walks just half of the distance, she will never reach the end because despite she has very near of the end, she will continue walking just half and ever smaller distances.

3 0

3 years ago

Please help me thank you I’ll mark Brainly

Inessa05 [86]

Answer:

the answer would be d

Step-by-step explanation:

(8+12) is the sum

(8+12)10 would give you the answer of the sum of 8 and 12 times 10

7 0

3 years ago

Read 2 more answers

"A cable TV company wants to estimate the percentage of cable boxes in use during an evening hour. An approximation is 20 percen

Marizza181 [45]

Answer:

The company should take a sample of 148 boxes.

Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± $Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ ]

Where

p' is the sample proportion/point estimator of the population proportion

$Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ is the margin of error (d) of the confidence interval.

$Z_{1-\alpha /2} = Z_{1-0.05} = Z_{0.95}= 1.648$

$d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$

$d *Z_{1-\alpha /2}= \sqrt{\frac{p'(1-p')}{n} }$

$(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}$

$n*(d*Z_{1-\alpha /2})^2= p'(1-p')$

$n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}$

$n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}$

n= 147.28 ≅ 148 boxes.

I hope it helps!

3 0

4 years ago

Katie draws two chords in a circle in a certain way. She then draws in four segments between adjacent endpoints of the chords to

FromTheMoon [43]

Answer: The answer that is not true is choice D.

If Katie drew those chords and those line segments to form a square, then the diagonals would have to be congruent. The only way to have them would be through the center, therefore they must be diameters.

And if it is a square, then the diagonals are perpendicular bisectors meaning the angles would be right angles not acute or obtuse as in Choice D. <span />

7 0

3 years ago