Given the function f defined by the formula f(x)=x^2-4 find the following: (a) f(3) (b) f(-4) (c) f(0) (d) (-2)

The amount of money that remains from a 20-dollar bill after Malina buys 4 party favors for p dollars each is 20 - 4p. Find the

vlada-n [284]

P = the money, so...
20 - ( 4 times 3)
20 - 12
8. She has $8 remaining. Hope it helps! I you could vote me brainliest, that would be awesome!

3 0

3 years ago

Please help asap.<br><br> please don’t take advantage of the points.

Verdich [7]

The answer is c = .6x + 5

In order to find the equation, note that the price per pound is contingent upon the weight in x. Therefore, we can multiply the two together.

We also need to add the constant, which is 5.

5 0

2 years ago

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A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. The standard deviation of the amount in

erica [24]

Answer:

$\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54$

The degrees of freedom are:

$df=n-1=10-1=9$

Now we can calculate the p value using the alternative hypothesis:

$p_v =2*P(\chi^2 >13.54)=0.279$

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$n=10$ represent the sample size

$\alpha=0.05$ represent the confidence level

$s^2 =0.0217$ represent the sample variance

$\sigma^2_0 =0.12^2= 0.0144$ represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 = 0.0144$

Alternative hypothesis: $\sigma^2 \neq 0.0144$

The statistic can be calculated like this;

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

$\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54$

The degrees of freedom are:

$df=n-1=10-1=9$

Now we can calculate the p value using the alternative hypothesis:

$p_v =2*P(\chi^2 >13.54)=0.279$

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

7 0

2 years ago

Give an example of a job that would have a y-intercept of $0 and another with a y-intercept of $20. What do these y-intercepts m

strojnjashka [21]

Answer

I) A job pays $15/hr with no bonus first day pay.

II) A job pays $15/hr with a $20 bonus first day pay.

Step-by-step explanation:

The y-intercepts would represent additional income that is added on to the base wage. It means it is what the worker would already earn (one-time), adding on to their standard pay.

Let X represent hours, and the y-intercept be what is mentioned above.

I) 15x + 0

II) 15x + 20

6 0

2 years ago

What is the sales tax of a $249 cell phone if the tax rate is 8%

raketka [301]

$19.92 is the answer

7 0

3 years ago

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