Which function has a graph with a horizontal asymptote at y = 3, a vertical asymptote at x = 1, and an x-intercept at 2?

Write a function g whose graph is a translation 2 units to the left of the graph of f (x) = |x| - 5

White raven [17]

A function is g(x) = |x+2| - 5 whose graph is a translation 2 units to the left of the graph of f (x) = |x| - 5.

<h3>What is a function?</h3>

A function is defined as the expression that set up the relationship between the dependent variable and independent variable. A graph is the representation of the data on the vertical and horizontal coordinates so we can see the trend of the data.

The given function f(x) = |x| - 5 after transaltion of the graph by 2 units left will become g(x) = |x+2| - 5.

The graph of the function is attached with the answer below. In which both functions are graphed.

Therefore, afunction is g(x) = |x+2| - 5 whose graph is a translation 2 units to the left of the graph of f (x) = |x| - 5.

To know more about functions follow

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6 0

2 years ago

Triangle RST has vertices R(−2, 2), S(1, 1), and T(−1, −3). Find the coordinates for the image of each vertex for the given rota

Vesnalui [34]

Answer:

A. $R'(-2,-2),S'(-1,1),$ and $T'(3,-1)$

Step-by-step explanation:

Given:

Vertices of triangle RST are $R(-2,2),S(1,1),$ and $T(-1,-3)$ .

Rotation is 90° about the center O(0,0). The rotation is counter-clockwise as the angle of rotation is positive.

Now, the co-ordinate rule for 90° rotation counter-clockwise is given as: $(x,y)$ → $(-y,x)$

$x$ and $y$ values interchange their places with $y$ becoming negative when interchanged.

So, $R(-2,2)$ → $R'(-2,-2)$

$S(1,1)$ → $S'(-1,1)$

$T(-1,-3)$ → $T'(-(-3),-1)$

⇒ $T(-1,-3)$ → $T'(3,-1)$

Therefore, the image of the vertices are $R'(-2,-2),S'(-1,1),$ and $T'(3,-1)$ .

6 0

3 years ago

According to Inc, 79% of job seekers used social media in their job search in 2018. Many believe this number is inflated by the

Fynjy0 [20]

Answer:

Null hypothesis: $p\leq 0.79$

Alternative hypothesis: $p > 0.79$

$z=\frac{0.849 -0.79}{\sqrt{\frac{0.79(1-0.79)}{370}}}=2.786$

$p_v =P(z>2.786)=0.00267$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the true proportion is higher than 0.79.

Step-by-step explanation:

1) Data given and notation

n=750 represent the random sample taken

X=314 represent the respondents that use social media in their job search.

$\hat p=\frac{314}{370}=0.849$ estimated proportion of respondents that use social media in their job search

$p_o=0.79$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is hgiher than 0.79.:

Null hypothesis: $p\leq 0.79$

Alternative hypothesis: $p > 0.79$

When we conduct a proportion test we need to use the z statisticc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.849 -0.79}{\sqrt{\frac{0.79(1-0.79)}{370}}}=2.786$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>2.786)=0.00267$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the true proportion is higher than 0.79.

7 0

3 years ago

Can you help with this

Komok [63]

Answer:

x = 27, and y = 47.

Step-by-step explanation:

AB is a line, so the measures of the angles measuring

2x + 1, 3x + 10, and 8/9 x + 10

add to 180 degrees. We can use that fact to find x.

2x + 1 + 3x + 10 + 8/9 x + 10 = 180

Add like terms on the left side except for the faction.

5x + 8/9 x + 21 = 180

Multiply both sides by 9.

45x + 8x + 189 = 1620

Add like terms on the left side. Subtract 168 from both sides.

53x = 1431

Divide both sides by 53.

x = 27

The angle measuring 3x + 10 is vertical with the angle that is made up of the measures y - 3 and y. Therefore, the sum of the measures y - 3 and y equals the measure 3x + 10. We know x, so we can find 3x + 10.

3x + 10 = 3(27) + 10 = 91

Now we set the sum of y - 3 and y equal to 91 and solve for y.

y - 3 + y = 91

2y - 3 = 91

2y = 94

y = 47

x = 27, and y = 47.

8 0

3 years ago

Solve all please! step by step too!

Nuetrik [128]

1) x=100
2) m=1000
3) v=49
4) v=64
5)n=81
6) x=22
7) b=1
8) b=-8

8 0

3 years ago