I am thinking you mean 93 to represent William's scores of 91, 92, and "q3"on three quizzes in Queston 8a
Answer:Average (x)= 92
b.William needs 97 as his third score to get as average of 90
Step-by-step explanation:
a.
The Average ( x) of the scores can solved using the Formulae
Average ( x)= Sum of scores / Number of Scores
Average ( x) = (Score 1 + Score 2 + Score 3) /3
Average (x)= (91, 92, and 93 )/3=276/3 = 92
b) Average ( x) of the scores = Sum of scores/ Number of Scores
Now let Score be represented as S such that
Average (x) = (S 1 + S 2 + S3 )/ 3
90 = 85+ 88+ S/ 3
90 x 3= 85+ 88 + S
270=173+ S
S= 270- 173
S=97
William needs 97 as his third score to get as average of 90
Answer:
I think it is the second one
Answer:
the domain is -11,10 but i didnt know if you wanted that or not
Step-by-step explanation:
Answer:
Find the prime factorization of 14
14 = 2 × 7
Find the prime factorization of 6
6 = 2 × 3
Multiply each factor the greater number of times it occurs in steps i) or ii) above to find the lcm:
LCM = 2 × 3 × 7
LCM = 42
Answer:
67
Step-by-step explanation:
2b+9r
2(2)+9(7)
4+63
67
